> I have what I think is a string from socket.recvfrom(...). I want to
> turn it into numbers
Hi Frank,
If you know how those bytes should be interpreted, you may want to look at
the 'struct' module to destructure them back into integers:
http://www.python.org/doc/lib/module-struct.html
> from socket import *
> from array import *
Side note: you may want to avoid doing the 'from <foo> import *' form in
Python, just because there's a high chance that one module will munge the
names of another. If you want to avoid typing, you can always abbreviate
module names by doing something like this:
######
import socket as S
import array as A
######
For more information on this, see:
http://www.python.org/doc/tut/node8.html#SECTION008410000000000000000
Ok, let's continue looking at some code:
[some code cut]
> number =int(s.join(data[10:13],16))
I think you meant to write:
number = int(data[10:13], 16)
But even with the correction, this will probably not work: int() expects
to see string literals, not arbitrary byte patterns that come off the
socket.recv_from.
I think you want to use 'struct' instead. For example:
######
>>> import struct
>>> struct.calcsize("h")
2
######
On my platform, a "short" is two bytes.
######
>>> def parse_short(bytes):
... """Given two bytes, interprets those bytes as a short."""
... return struct.unpack("h", bytes)[0]
...
>>> parse_short('\x01\x00')
1
>>> parse_short('\x00\x01')
256
######
And from this example, we can see that I'm on a "little-endian" system.
http://catb.org/~esr/jargon/html/L/little-endian.html
So we probably do need to take care to tell 'struct' to interpret the
bytes in "network" order, bu using the '!' prefix during the byte
unpacking:
######
>>> def parse_short(bytes):
... """Given two bytes, interprets those bytes as a short."""
... return struct.unpack("!h", bytes)[0]
...
>>> parse_short('\x01\x00')
256
>>> parse_short('\x00\x01')
1
######
Please feel free to ask questions on this. Hope this helps!
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