Ummm...that doesn't do what I asked. pop is a linguistic idiom for
(val, mylist) = (mylist[-1], mylist[0:-1]) shift is the standard idiom for (val, mylist) = (mylist[0], mylist[1:]) but Python doesn't appear to offer this. Jeff -----Original Message----- From: Kent Johnson [mailto:[EMAIL PROTECTED] Sent: Wednesday, August 03, 2005 9:15 AM Cc: tutor@python.org Subject: Re: [Tutor] Deleting an entry from a dictionary Smith, Jeff wrote: > Speaking of which, I note that there is a pop for lists but no shift. > Is there a Python idiom for this or is it just > val = mylist.shift() => (val, mylist) = (mylist[0], mylist[1:]) > which seems a little clumsy. val = mylist.pop(0) Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
