The following code: print str(dict(a=1,b=2,c=-1)) print str(dict(a=1,c=-1,b=2)) print str(dict(c=-1,a=1,b=2)) print str(dict(b=2,a=1,c=-1)) print str(dict(b=2,c=-1,a=1)) print print str(dict(a=1,b=2,c=23)) print str(dict(a=1,c=23,b=2)) print str(dict(c=23,a=1,b=2)) print str(dict(b=2,a=1,c=23)) print str(dict(b=2,c=23,a=1)) print print str(dict(a=1,b=2,c='booga')) print str(dict(a=1,c='booga',b=2)) print str(dict(c='booga',a=1,b=2)) print str(dict(b=2,a=1,c='booga')) print str(dict(b=2,c='booga',a=1))
Produces: {'a': 1, 'c': -1, 'b': 2} {'a': 1, 'c': -1, 'b': 2} {'a': 1, 'c': -1, 'b': 2} {'a': 1, 'c': -1, 'b': 2} {'a': 1, 'c': -1, 'b': 2} {'a': 1, 'c': 23, 'b': 2} {'a': 1, 'c': 23, 'b': 2} {'a': 1, 'c': 23, 'b': 2} {'a': 1, 'c': 23, 'b': 2} {'a': 1, 'c': 23, 'b': 2} {'a': 1, 'c': 'booga', 'b': 2} {'a': 1, 'c': 'booga', 'b': 2} {'a': 1, 'c': 'booga', 'b': 2} {'a': 1, 'c': 'booga', 'b': 2} {'a': 1, 'c': 'booga', 'b': 2} Could I rely on creating hashes to use as keys in bsddb this way? If I create a dictionary with the same keys, will it str the same way? Thanks! -- *********************************** See there, that wasn't so bad. *********************************** _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor