Reed L. O'Brien wrote:
>Luis N wrote:
>
>
>
>>Hi,
>>
>>
>>
>>>>>l
>>>>>
>>>>>
>>[{'last': 'Bar', 'first': 'Foo'}, {'last': 'Bar', 'first': 'Foo'},
>>{'last': 'Bar', 'first': 'Foo'}, {'last': 'Bar', 'first': 'Foo'}]
>>
>>
>>This is how I imagine it:
>>
>>for i in l:
>> for j in l[i]:
>> for k in l[i][j]:
>> print k.get('first')
>> print k.get('last')
>>
>>Is there a short and sweet way of doing this (that actually works).
>>
>>Luis.
>>
>>
>
>
>strings back:
>
>for i in l:
> x = l[0].values()
> x.reverse()
> print " ".join(x)
>
>Foo Bar
>Foo Bar
>Foo Bar
>Foo Bar
>
>lists back:
>
>for i in l:
> x = l[0].values()
> x.reverse()
> print x
>
>
>['Foo', 'Bar']
>['Foo', 'Bar']
>['Foo', 'Bar']
>['Foo', 'Bar']
>
>~r
>
>
>
>
I take that back now that I read it it is returning only the first one 4
times
oops
~r
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