Try this.
#######################################
old_group_delimiter = "\n\n" old_line_delimiter = "\n" new_group_delimiter = "\n" new_line_delimiter = ", "
fi = raw_input("Input file to use? ")
fi = open(fi,"r")
stuff = fi.read()
fi.close()
addressgroups = stuff.split(old_group_delimiter)
addressgroups = [x.split(old_line_delimiter) for x in addressgroups]
addressgroups = [new_line_delimiter.join(x) for x in addressgroups]
newtext = new_group_delimiter.join(addressgroups)fi = raw_input("Output file to use? ")
fi = open(fi,"w")
fi.write(newtext)
fi.close()#######################################
But your probably using re to study it, though. Just an alternative option. I'm trying to keep all the different ways in my head you know...
Jacob S.
The following program takes text data like this: Jimi Hendrix 2100 South Ave Seattle, WA 55408
and changes it to this
Jimi Hendrix, 2100 South Ave,Seattle,WA,55488
and writes it to a file. The problem I'm running into is that it only writes this first address to a file and there are several others in the file. I believe it has something to do with using re.search instead of re.findall. But re.findall returns a error when I try using it. Suggestions? Thanks in advance. Here is the script:
import re f = open('reformat.txt').read() pat = re.compile(r"([^\r\n]+)\n([^\r\n]*)\n([^\r\n]*) ([^\r\n]*) ([^\r\n]*)") x=re.search(pat,f) name = x.group(1) address = x.group(2) citystate = x.group(3)+x.group(4) zipcd = x.group(5) o= open('reformat1.txt','w') o.write("%s,%s,%s,%s\n" % (name, address, citystate,zipcd)) o.close() print("%s,%s,%s,%s\n" % (name, address, citystate,zipcd))
__________________________________ Do you Yahoo!? Yahoo! Small Business - Try our new resources site! http://smallbusiness.yahoo.com/resources/ _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
