I'm sorry, but when does oThread get the value 1? If you're testing for it's existence via a True/False thing, try
if oThread: But otherwise, I'm not sure what you're expecting to get. On Tue, 15 Feb 2005 20:58:15 -0500, Bernard Lebel <[EMAIL PROTECTED]> wrote: > Hello, > > I have already messed a little with simple thread programming, wich took > this form: > > from threading import Thread > > def mainFunction(): > pass > > Thread( target=mainFunction ).start() > > Now, I have a list of "jobs", each job being a windows bat file that > launches an executable and performs a rendering task. So I have this > queue of jobs, and would like to launch one only when the previous one > has finished, and in a separate window. So far I have not been having > much success with simple stuff: > > from threading import Thread > > def mainFunction(): > print 'function print' > return 1 > > for i in range( 0, 3 ): > oThread = Thread( target=mainFunction ).start() > > if oThread == 1: > print 'sleeping 3 seconds' > time.sleep( 3 ) > > In this example, 'sleeping 3 seconds' not returned, and each thread is > started without any waiting. > > I'm looking at the various threading module details in the library but I > have to admit that, well, I'm a bit at loss here. > > Thanks in advance > Bernard > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > -- 'There is only one basic human right, and that is to do as you damn well please. And with it comes the only basic human duty, to take the consequences. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
