f = open('text.txt').read() print f.count('word')
Other than using a several print statments to look for seperate words like this, is there a way to do it so that I get a individual count of each word:
word1 xxx word2 xxx words xxx
etc.
Someone else might offer a better way of finding such information in a file, but for now I'll assume that this method is okay and just answer your original question. I'd do it like this (untested):
f = open('text.txt').read()
words = ['word', 'beef', 'nachos', 'recipe']# This makes a list of tuples like [('word', 5), ('beef', 0), ...]
# You might also consider using a dictionary.
count = [(word, f.count(word)) for word in words]# Now print the results. for result in count: print "%s was found %d times." % result
# Dictionary method: # Uses the same list comprehension, maybe there's a better way? count = dict([(word, f.count(word)) for word in words])
for key, value in count.iteritems():
print "%s was found %d times." % (key, value)-- Brian Beck Adventurer of the First Order
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