Dear group:
I think I have got the answer :-)(
script:
>>> for i in range(len(psl)):
col = split(psl[i],'\t')
col1 = col[0]
col1 = int(col1)
col17 = int(col[17])
if col1 == 25 and col17 == 1:
print col[0]+
'\t'+col[1]+'\t'+col[9]+'\t'+col[10]+'\t'+col[11]
25 0 580:683 25 0
25 0 581:687 25 0
25 0 434:9 25 0
25 0 37:141 25 0
25 0 219:629 25 0
25 0 462:87 25 0
25 0 483:409 25 0
25 0 354:323 25 0
25 0 624:69 25 0
25 0 350:239 25 0
Is this a correct approach?
Thanks
K.
--- kumar s <[EMAIL PROTECTED]> wrote:
> Dear group,
> For some reason my brain cannot think of any other
> option than what I have in my script. Could any one
> please help me in suggesting.
>
> What I have : (File name : psl)
> 22 2 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 22 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
> 24 1 457:411 25 0
> 22 0 457:411 25 0
> 21 0 457:411 25 0
> 25 0 457:411 25 0
> 25 0 457:411 25 0
>
>
> What to do:
> I want to print values that are 25 in column 1 and
> not
> the other values such as 24,22,21 etc.
>
>
> My script:
> >>> for i in range(len(psl)):
> col = split(psl[i],'\t')
> col1 = col[0]
> if col1 == 25:
> print col[0]+'\t'+col[1]+'\t'+col[17]
>
>
> >>>
>
> Result: I get nothing. Am I doing something very
> wrong. Why isnt if col1 == 25: functional.
>
> My idea is to check if col[0] == 25: then print
> columns 1,18 etc.
>
> Can you please help me.
>
> Thanks
> K
>
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