Hi all, I'm playing with a file, and attempting to replace a section with a string, and using the following command -
seg=codeSt[element:endInd+len(endStr] codeSt=codeSt.replace(seg, hrefString) At the replace, I get a MemoryError. It's part of a for loop, but it gives the error the first time around. The Python docs say - "Raised when an operation runs out of memory but the situation may still be rescued (by deleting some objects). The associated value is a string indicating what kind of (internal) operation ran out of memory. Note that because of the underlying memory management architecture (C's malloc() function), the interpreter may not always be able to completely recover from this situation; it nevertheless raises an exception so that a stack traceback can be printed, in case a run-away program was the cause. " codeSt is a loaded text file that's 228Kb in size. The for loop that the above code is embedded in, generates a slightly new codeSt each time. Now, I had imagined that codeSt=codeSt+10 would destroy the old codeSt in memory and create a new codeSt. Am I right? Because, even if the for loop (which will iterate 267 times) were to keep a new copy of codeSt in memory, it should only need 59Mb of RAM, when I've got near half a gig of RAM and virtual memory. So yeah, I don't know how to troubleshoot this one. Full code is here - http://www.rafb.net/paste/results/ZflMyz31.html Any help that can be offered gratefully appreciated. I don't want to to have to learn C++? Malloc has an evil reputation. Oh, and Python 2.3.4, Windows XP Pro SP1, Athlon 650MHz, 256Mb RAM 20Gb HD, which has 1.6Gb free. In case any of that infos relevant. : ) Regards Liam Clarke -- 'There is only one basic human right, and that is to do as you damn well please. And with it comes the only basic human duty, to take the consequences. _______________________________________________ Tutor maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/tutor
