> from
> https://github.com/the-tcpdump-group/tcpdump/issues/333
>
> details an issue where differences in arch and compiler result in different
> extractions of floating point objects in LMP packets. Guy discovers it has
> something to do with assumptions about x86 SSE.
>
> and I think we might find more expertise on the list.
You need to read the C standard as well.
The C standard certainly allows 'double' arithmetic to be done
using the 80bit x87 80bit registers without requiring that
intermediate values (even those assigned to (implicit) register
variables) being truncated to 64bits.
I suspect that is a general statement about floating point precision.
Either that or there is something that allows 'float' arithmetic be
performed as 'float' or by converting to 'double'.
This means that expression below can be calculated with 32bit, 64bit
or 80bit intermediaries depending on the whim of the implementation.
Passing an appropriate -march=xxx will allow 32bit code use SSE
instructions - but portable code shouldn't enforce it.
David
>
> Date: Mon, 30 Sep 2013 16:31:47 -0700
> Subject: Re: [tcpdump] IEEE float decoded incorrectly (#333)
>
> So if I compile
>
> float
> xxx(float f)
> {
> return f*8/1000000;
> }
>
> with gcc -O2 -m32 -S, I get
>
> xxx:
> .LFB0:
> .cfi_startproc
> flds .LC0
> fmuls 4(%esp)
> fdivs .LC1
> ret
> .cfi_endproc
>
> and if I compile it with gcc -O2 -S (64-bit), I get
>
> xxx:
> .LFB0:
> .cfi_startproc
> mulss .LC0(%rip), %xmm0
> divss .LC1(%rip), %xmm0
> ret
> .cfi_endproc
>
> So the 32-bit code is using the x87 instructions, using the 80-bit registers
> on
> the stack, and doing 80-bit extended-precision arithmetic, and the 64-bit code
> is using SSE instructions, and presumably doing 32-bit single-precision
> arithmetic; the Intel manuals don't explicitly say that the single-precision
> scalar floating point SSE instructions perform single-precision arithmetic on
> their single-precision operands, but that's my guess - somebody more
> knowledgable than I am about IEEE floating point could probably answer this,
> and, even if it's double-precision, that's still different from
> extended-precision.
>
> I.e., it's a consequence of i686 not being guaranteed to have SSE (it was
> introduced in the Pentium III, not the Pentium Pro), so that compiling for
> i686
> means using the x86 instructions for floating point, and the x86 instructions
> doing everything in 80-bit extended precision, not of the use of a union.
>
> Sadly, the obvious choice of configuring with CFLAGS="-m32 -mfpmath=sse"
> doesn't help - the compiler decides, for some reason, that I didn't really
> mean
> -mfpmath=sse and says "hey, 32-bit x86 isn't guaranteed to have SSE, so I'm
> just going to build with x86 instructions" (or, as it puts it, "warning: SSE
> instruction set disabled, using 387 arithmetics [enabled by default]"), and
> some other things I tried, such as -mtune=pentium3, didn't help. I'll leave it
> to somebody more familiar with GCC-wrangling to figure out how to beat GCC
> into
> producing 32-bit code that uses SSE rather than x87 floating-point
> instructions, but I suspect that, if you build a 32-bit tcpdump with whatever
> options those are, make check will succeed, at least on those tests.
>
> (32-bit tcpdump is failing with some other problems as well; I'll check
> whether
> they're also problems with 64-bit tcpdump, and see what's going on there.)
>
>
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