i use dih to create index on oracle table
data table:tab_post_content
---id-----content(varchar2 4000)------: for example
0001 i have an ipad and Seagate hd
industry word table: tab_iword
--code-----word-----: for example
01/00/00 computer
01/01/00 cpu
01/01/01 intel
01/01/02 amd
01/02/00 hard disk
01/02/01 Seagate
01/02/02 westwood
02/00/00 mobile
02/01/00 phone
02/01/01 sumsung
02/01/00 iphone
02/02/00 pad
02/02/01 ipad
02/02/02 xpad
schema.xml snippet
<fieldType name="iword_tag" class="solr.TextField">
<analyzer type="index">
<tokenizer class="solr.IwordTokenizerFactory"
tab_iword="tab_iword.txt"/>
</analyzer>
<analyzer type="query">
<tokenizer class="solr.KeywordTokenizerFactory"/>
</analyzer>
</fieldType>
</types>
<field name="id" type="string" indexed="true" stored="true"
required="true"/>
<field name="content" type="text" indexed="true" stored="true"
required="false"/>
<field name="iword" type="iword_tag" indexed="true" stored="true"
required="false" multiValued="true"/>
dih-db-config.xml entity snippet
<entity name="test" query="select id,content,content as iword from
tab_post_content" transformer="RegexTransformer,..">
<field column="id" name="id" />
<field column="content" name="content" />
<field column="iword" name="iword"/>
</entity>
how to write custom code IwordTokenizerFactory?
the solr index will return is like this
<doc>
<str name="id">0001</str>
<str name="content">i have an ipad and Seagate hd</str>
<arr name="iword">
<str>02/02/01</str>
<str>01/02/01</str>
</arr>
<doc>
thanks.
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