Prateesh: I'm not understanding here. I believe Tamanjit is correct. Your example works if and only if *all* the groups are returned, which happens in the example case but not in the general case. Try your experiment with
&rows=3 and you'll find that (trunk, example) This search: http://localhost:8983/solr/select?q=*:*&group=true&group.field=manu_exact&group.ngroups=true&rows=3 returns this (lots of stuff removed for clarity) <response> <lst name="responseHeader"> <lst name="params"> <str name="group.field">manu_exact</str> <str name="group.ngroups">true</str> <str name="group">true</str> <str name="q">*:*</str> <str name="rows">3</str> </lst> </lst> <lst name="grouped"> <lst name="manu_exact"> <int name="matches">28</int> <int name="ngroups">13</int> <arr name="groups"> <lst> <null name="groupValue"/> <result name="doclist" numFound="12" start="0"> </result> </lst> <lst> <str name="groupValue">Samsung Electronics Co. Ltd.</str> <result name="doclist" numFound="1" start="0"> </result> </lst> <lst> <str name="groupValue">Maxtor Corp.</str> <result name="doclist" numFound="1" start="0"> </result> </lst> </arr> </lst> </lst> </response> Sum of numfounds is different than matches. Or perhaps I'm misunderstanding your example... Best Erick On Fri, Feb 3, 2012 at 12:46 AM, preetesh dubey <dubeypreet...@gmail.com> wrote: > Nope! > if u r doing grouping then "matches" is always the total no. of results and > "ngroups" is the number of groups. Every groups can have some docs > belonging to it which can be anything according to provided parameter > "group.limit". If u get the sum of all the docs of each group, then it's > equivalent to "matches". > Ok.....u can do one experiment.....execute a simple query in solr which > returns very few results. > 1)execute the query *without grouping* in browser and check the xml/json > response...it will show u the total no. of result matches as a response in > "numFound"...e,g. > <result name="response" numFound="20" start="0"> > lets say it..... > *a)* numFound*withoutgrouping=20* > 2) Now execute the query same *with grouping *parameters* *and* *look at > the xml/json response in browser. it will show u the results like this.... > /********** > <lst name="groupid"> > <int name="matches">20</int> > <int name="ngroups">12</int> > <arr name="groups"> > <lst> > <str name="groupValue">4362</str> > <result name="doclist" numFound="1" start="0">...</result> > </lst> > <lst> > <str name="groupValue">3170</str> > <result name="doclist" numFound="3" start="0">...</result> > </lst> > **********/ > > b)matcheswithgroups=20 > > Now do the sum of docs of every group... > <result name="doclist" numFound="1" start="0">...</result> > <result name="doclist" numFound="3" start="0">...</result> > sum of numFound="1", numFound="3" ..... > lets say > * > * > *c) sumofgroups*=1+3+.......u will find a==b==c at last..... > do that experiment and reply back...... > > after doing sum compare the a), b), c) > > On Fri, Feb 3, 2012 at 10:32 AM, tamanjit.bin...@yahoo.co.in < > tamanjit.bin...@yahoo.co.in> wrote: > >> Ummm.. I think there is some confusion here. >> >> As per my understanding, matches is the total no of docs which the original >> query/filter query returned. On these docs grouping is done. So matches may >> not be actually equal to total no. of returned in your result, post >> grouping. Its just a subset of the matches, divided into groups. >> >> Is my understanding correct? >> >> -- >> View this message in context: >> http://lucene.472066.n3.nabble.com/Which-patch-236-to-choose-for-collapse-Solr-3-5-tp3697685p3712195.html >> Sent from the Solr - User mailing list archive at Nabble.com. >> > > > > -- > Thanks & Regards > Preetesh Dubey
