This was my mistake. Thank you. Taisuke
2020年10月23日(金) 15:02 Taisuke Miyazaki <miyazakitais...@lifull.com>: > Thanks. > > I analyzed it as explain=true and this is what I found. > Why does this behave this way? > > fq=foo:1 > bq=foo:(1)^1 > bf=sum(2000000) > > If you do this, the score will be boosted by bq. > However, if you remove fq, the score will not be boosted by bq. > However, if you change the boost value of bq to 2, bq will be boosted > regardless of whether you have fq or not. > > This behavior seems very strange to me. (I'm not familiar with the > internals of Solr or Lucene). > > By the way, this doesn't happen if you change the sum number to a value > that doesn't need to be expressed as an exponent. (20,000,000 is marked as > 2.0E7 on EXPLAIN.) > > Regards, > Taisuke > > 2020年10月22日(木) 21:41 Erick Erickson <erickerick...@gmail.com>: > >> You’d get a much better idea of what goes on >> if you added &explain=true and analyzed the >> output. That’d show you exactly what is >> calculated when. >> >> Best, >> Erick >> >> > On Oct 22, 2020, at 4:05 AM, Taisuke Miyazaki < >> miyazakitais...@lifull.com> wrote: >> > >> > Hi, >> > >> > If you use a high value for the score, the values on the smaller scale >> are >> > ignored. >> > >> > Example : >> > bq = foo:(1.0)^1.0 >> > bf = sum(2000000) >> > >> > When I do this, the additional score for "foo" at 1.0 does not affect >> the >> > sort order. >> > >> > I'm assuming this is an issue with the precision of the score floating >> > point, is that correct? >> > >> > As a test, if we change the query as follows, the order will change as >> you >> > would expect, reflecting the additional score of "foo" when it is 1.0 >> > bq = foo:(1.0)^10 >> > bf = sum(2000000) >> > >> > How can I avoid this? >> > The idea I'm thinking of at the moment is to divide the whole thing by >> an >> > appropriate number, such as bf= div(sum(2000000),100). >> > However, this may or may not work as expected depending on when the >> > floating point operations are done and rounded off. >> > >> > At what point are score's floats rounded? >> > >> > 1. when sorting >> > 2. when calculating the score >> > 3. when evaluating each function for each bq and bf >> > >> > Regards, >> > Taisuke >> >>
