Hello everyone,thanks for the prompt reply! In response to Florian, I can get correct score only when boost for 1 filed (for example category): the score are correctly increased by the factor.But when I try to make a double boost, the score are not great as expected (for example, if the greatest boost factor for category is 3 and for source is 3, sometimes I've got documents boosted with category^3 and source^1 **before** documents boosted with category^3 and source^3). I tired you snippet code "^=[boost]" instead of "^[factor]" but seems not work for me: SyntaxError: Cannot parse 'category:9500^': Encountered \"<EOF>\" at line 1 (...) In response to Erik, I have different "sort preferences", so I can't build a index and use for sorting.Maybe I have to sort by category then by source and by language or by source, then by category and by date.The sort function that you are talking is a custom sort function of Solr?I build a custom PHP method that sort documents queried from Solr and it works good: the problem is that if I choose this way I have to get **all** the results in a single query and I can't paginate.Today I have millions of record and query could be very large, I would like to paginate results.To paginate results I need that Solr give me the results query in the correct order.Thank you very much
Luca On Monday, July 17, 2017 6:04 PM, Erick Erickson <erickerick...@gmail.com> wrote: I don't think boosting is really what you want here. Boosting _influences_ the score, it does not impose an ordering. Sorting _does_ impose an ordering, the question is how to sort and the answer depends on how fixed (or not) the sorting criteria are. Do they change with different queries? If not, the very simplest thing to do is to index a field with a pre-computed sort value. IOW, if your ordering is _always_ source 5, 9, 7 index a source_sort field that orders things that way and sort on that. Then I'd have a secondary sort by score as a tie-breaker. If that's not the case, perhaps sorting by function (perhaps a custom function) would work. Best, Erick On Mon, Jul 17, 2017 at 4:30 AM, Florian Waltersdorfer <florian.waltersdor...@compass.at> wrote: > Hi, > > I am quite the SolR newbie myself, but have you looked at the resulting > scores, e.g. via fl=*,score (that way, you can see/test how your boosting > affects the results)? > In a similar scenario, I am using fixed value boosts for specific field > values; "^=[boost]" instead of "^[factor]", for example: > > category:9500^=20 source:(5^=20 OR 9^=10 OR 7^=5) > > (Actual fixed values open for experimentation.) > > Regards, > Florian > > -----Ursprüngliche Nachricht----- > Von: Luca Dall'Osto [mailto:tenacious...@yahoo.it.INVALID] > Gesendet: Montag, 17. Juli 2017 12:20 > An: solr-user@lucene.apache.org > Betreff: Get results in multiple orders (multiple boosts) > > Hello, > I'm new in Solr (and in mailing lists..), and I have a question about > querying contents in multiple custom orders. > I 'm trying to query some documents boosted by 2 (or more) fields: I'm able > to make a search of 2 day and return results boosted by category field, like > this: > > ?indent=on > &defType=edismax > &q=(date:[2017-06-16T00:00:00Z TO 2017-06-18T23:59:59Z]) > &bq=category:9500^2 > &bq=category:1100^1 > &rows=40 > &wt=jsonThis will return all documents of category 9500 first, and 1100 in > after.Now I would like to get this documents with a second boost based on > another field, called source.I would like to have documents in this order:1) > category:9500 AND source:5 > 2) category:9500 AND source:9 > 3) category:9500 AND source:7 > 4) category:1100 AND source:5 > 5) category:1100 AND source:9 > 6) category:1100 AND source:7 > To get this order, I tied with this query:?indent=on &defType=edismax > &q=(date:[2017-06-16T00:00:00Z TO 2017-06-18T23:59:59Z]) > &bq=category:9500^2+source:(5^3 OR 9^2 OR 7^1) > &bq=category:1100^1+source:(5^3 OR 9^2 OR 7^1) > &rows=40 > &wt=json > How can I apply a double boosts to get the documents in my correct order? Is > boost the correct tool for my purpose?Any help will be greatly appreciated. > Thanks Luca