glad it worked for you.  im planning on some experimentation using that
feature, could contribute to an interface nicely if thought through well.

On Tue, Mar 14, 2017 at 2:25 PM, Scott Smith <ssm...@mainstreamdata.com>
wrote:

> Grouping appears to be exactly what I'm looking for.  I added
> "group=true&group.field=category" to my search and It appears that I get
> a list of groups, one document in each group that matches the search along
> with (bonus) the number of documents in the category that match that
> search. Perfect.  Thank you very much.
>
> -----Original Message-----
> From: Dave [mailto:hastings.recurs...@gmail.com]
> Sent: Monday, March 13, 2017 7:59 PM
> To: solr-user@lucene.apache.org
> Subject: Re: Facet? Search problem
>
> Perhaps look into grouping on that field.
>
> > On Mar 13, 2017, at 9:08 PM, Scott Smith <ssm...@mainstreamdata.com>
> wrote:
> >
> > I'm trying to solve a search problem and wondering if facets (or
> something else) might solve the problem.
> >
> > Let's assume I have a bunch of documents (100 million+).  Each document
> has a category (keyword) assigned to it.  A single document my only have
> one category, but there may be multiple documents with the same category (1
> to a few hundred documents may be in any one category).  There are several
> million categories.
> >
> > Supposed I'm doing a search with a page size of 50.  What I want to do
> is do a search (e.g., "dog") and get back the top 50 documents that match
> the contain the word "dog" and are all in different categories.  So, there
> needs to be one document from 50 different categories.
> >
> > If that's not possible, then is it possible to do it if I know the 50
> categories up-front and hand that off as part of the search (so "find 50
> documents that match the term 'dog' and there is one document from each of
> 50 specified categories").
> >
> > Is there a way to do this?
> >
> > I'm not extremely knowledgeable about facets, but thought that might be
> a solution.  But, it doesn't have to be facets.
> >
> > Thanks for any help
> >
> > Scott
> >
> >
>

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