Hi Mikhail,
It won't solve my problem.
For ex:
Suppose my docs are like this:
<doc>
<field name="userid>1</field>
<doc>
<field name="address">city1</field>
</doc>
<doc>
<field name="address">city2</field>
</doc>
</doc>
<doc>
<field name="userid>2</field>
<doc>
<field name="address">city2</field>
</doc>
<doc>
<field name="address">city3</field>
</doc>
</doc>
Now if I want* a query to return me all the users not having any address*
related to *city1* (i.e. only userid=2 should be in the result)and then if
i query:
*q={!parent which=userid:*}*:* -address:city1*
This will return me two* results i.e.** userid=2 and userid=1 *(as userid=1
is also having a child whose address is city2) , *desired output was
userid=2 only.*
On Tue, Feb 17, 2015 at 8:12 PM, Mikhail Khludnev <
mkhlud...@griddynamics.com> wrote:
> try to search all children remove those who has a value1 by dash, then join
> remaining
> q={!parent which=contentType:parent}contentType:child -contentType:value1
> if the space in underneath query causes the problem try to escape it or
> wrap to v=$subq
>
>
>
> On Tue, Feb 17, 2015 at 4:13 PM, Sankalp Gupta <sankalp.gu...@snapdeal.com
> >
> wrote:
>
> > Hi
> >
> > I need to have a query in which I need to choose only those parent docs
> > none of whose children's field is having the specified value.
> > i.e. I need something like this:
> > http://localhost:8983/solr/core1/select?*q={!parent
> > which=contentType:parent}childField:NOT value1*
> >
> > The problem is* NOT operator is not being supported* in the Block Join
> > Query Parsers. Could anyone please suggest a way to workaround this
> > problem?
> > Have also added the problem on *stackoverflow*:
> >
> >
> http://stackoverflow.com/questions/28562355/in-solr-does-block-join-query-parsers-lack-regular-expression-feature
> >
> > Regards
> > Sankalp Gupta
> >
>
>
>
> --
> Sincerely yours
> Mikhail Khludnev
> Principal Engineer,
> Grid Dynamics
>
> <http://www.griddynamics.com>
> <mkhlud...@griddynamics.com>
>
