You could also return the top 50 groups. That will certainly contain the top 50 responses. The app layer could then do some local sorting to figure out what was correct. Maybe you'd be returning 3 docs in each or something...
I'd probably only go there if Michael's approach didn't work out though. On Fri, Jul 11, 2014 at 10:52 AM, Michael Ryan <mr...@moreover.com> wrote: > I suggest doing this in two queries. In the first query, retrieve the unique > ids of the top 50 documents. In the second query, just query for those ids > (e.g., q=ids:(2 13 55 62 81)), and add the facet parameters on that query. > > -Michael > > -----Original Message----- > From: Aaron Gibbons [mailto:agibb...@synergydatasystems.com] > Sent: Friday, July 11, 2014 1:46 PM > To: solr-user@lucene.apache.org > Subject: Group only top 50 results not All results. > > I'm trying to figure out how I can query solr for the top X results THEN > group and count only those top 50 by their owner. > > I can run a query to get the top 50 results that I want. > solr/select?q=(current_position_title%3a(TEST))&rows=50 > > I've tried Faceting but I get all results faceted not just the top 50: > solr/select?q=(current_position_title%3a(TEST))&start=0&rows=50&facet=true&facet.field=recruiterkeyid&facet.limit=-1&facet.mincount=1&facet.sort=true > > I've tried Grouping and get all results again grouped not just the top 50. > solr/select?q=(current_position_title%3a(TEST))&rows=50&group=true&group.field=recruiterkeyid&group.limit=1&group.format=grouped&version=2.2 > > I could also run one search to get the top X record Id's then run a second > Grouped query on those but I was hoping there was a less expensive way run > the search. > > So what I need to get back are the distinct recruiterkeyid's from the top X > query and the count of how many there are only in the top X results. I'll > ultimately want to query the results for each of individual recruiterkeyid as > well. I'm using SolrNet to build the query. > > Thank you for your help, > Aaron
