On Wed, 2008-10-22 at 11:01 +0700, Ivan Mikhailov wrote:
> Hello Sergio,
Hi Ivan,
> I'd add a newline to read the query as the parser reads it:
>
> SELECT DISTINCT
> (?name) ?person ?mail
> WHERE {
> ?person rdf:type foaf:Person .
> ?person foaf:name ?name .
> ?person foaf:mbox_sha1sum ?ma
Hello Sergio,
I'd add a newline to read the query as the parser reads it:
SELECT DISTINCT
(?name) ?person ?mail
WHERE {
?person rdf:type foaf:Person .
?person foaf:name ?name .
?person foaf:mbox_sha1sum ?mail
}
SELECT DISTINCT is as in plain SPARQL, return values are expression ?name and
On Tue, 2008-10-21 at 11:37 +0100, Hugh Williams wrote:
> Hi Sergio,
Hi Hugh,
> I would expect "DISTINCT" to work as I used it quite often in SPARQL
> queries against Virtuoso.
Me too. Works fine with a DISTINCT for whole elements in a SELECT.
> Can you provide a test case for us to see this pr
Hi Sergio,
I would expect "DISTINCT" to work as I used it quite often in SPARQL
queries against Virtuoso.
Can you provide a test case for us to see this problem first hand,
either a server instance we can access online or a dataset we can
load locally to recreate.
The Virtuoso explain f
Hi,
in a experiment I've a dataset with many people (some of then
duplicated). I want just to list it, I'm doing something like:
SELECT DISTINCT(?name) ?person ?mail
WHERE {
?person rdf:type foaf:Person .
?person foaf:name ?name .
?person foaf:mbox_sha1sum ?mail
}
But DISTINCT doesn't wor
