Hi Arun,
OAuth can be done programatically but it's a little convoluted to do so.
In anycase, Virtuoso supports other forms of authentication than OAuth.
https://virtuoso.openlinksw.com/dataspace/doc/dav/wiki/Main/VirtTipsAndTricksDigestAuthAJAX
You haven't mentioned what kind of applicati
Hi all,
I am trying to build a service that uses Virtuoso DB with DBpedia data.
I've got the setup to a point where the data is loaded and my client can
query the Virtuoso server using the public SPARQL endpoint. Now I want to
secure access to the server, ie allow only authorized applications to
a
Hi Ivan,
On Wed, Nov 2, 2016 at 12:32 PM, Ivan Mikhailov
wrote:
>
> How do you know that FILTER (STRLEN(?literal) = 8) is executed before
> SUBSTR(?literal, 8, 1) ?
FILTER is placed before SUBSTR in the WHERE clause. SPARQL optimizer may
(incorrectly) switch that order.
> What's the full text
Hello Jindřich,
How do you know that FILTER (STRLEN(?literal) = 8) is executed before
SUBSTR(?literal, 8, 1) ? What's the full text of the query?
Virtuoso translates SPARQL to SQL and uses all allowed term rewritings
and other tricks trying to get highest possible speed. As a side effect,
the ord
Hello Jerven,
good catch. Now, I'm wondering whether BIND has to be evaluated after
the FILTER or if this isn't specified in the SPARQL standard. Or does
the order in the SPARQL query matters in that case like it does for
OPTIONAL clauses?
Kind regards,
Lorenz
> Hi All,
>
> I think it is an is
Hi All,
I think it is an issue in the way that the xpath spec is included in the
SPARQL 1.1 spec, in an unclear manner.
e.g.
SELECT *
WHERE
{
VALUES ?s { "abc" "abcd" "abd" "AB" "" UNDEF "AA" }
BIND(substr(str(?s), 3, 1) AS ?lastChar)
}
Gives an error as described. B
Hi Lorenz,
I also could not replicate the behaviour with VALUES. If that was possible,
that would make diagnosing it much simpler. It seems it is caused by some
side effects.
The original query is at
https://github.com/jindrichmynarz/vvz-to-rdf/blob/f8d421002eef19359ffd89b0d209b47e87b2ee0e/sparql
Hello Jindřich,
can you show the query maybe?
I couldn't reproduce this with some dummy data produced by VALUES, but I
don't know how you use FILTER and substring afterwards:
SELECT *
WHERE
{ { SELECT *
WHERE
{ VALUES ?s { "abc" "abcd" "abd" } }
}
FILTER ( strlen(str(
Hi Hugh,
producing a minimal test case to reproduce the behaviour is indeed the
difficult part. I've been trying to do that without success. So far I'm
able to replicate the behaviour only with my full database. I'll reopen
this if I manage to narrow down the data required to replicate the
behavio
