Ok, I discovered that passing Statement instead of string to
executeAsync method solves a problem:
https://github.com/afiskon/scala-cassandra-example/commit/4f3f30597a4df340f739e4ec53ec9ee3d87da495
Still, according to documentation for getQueryString method described
problem should be considered
Hello.
I'm having some problems with Cassandra driver for Java.
Here is a simple Scala project:
https://github.com/afiskon/scala-cassandra-example
When I run it I get following output:
http://paste.ubuntu.com/11767987/
As I understand this piece of code:
```
private val id = "id"
private val
