foo. Will this work?
>
> From: aaron morton [mailto:aa...@thelastpickle.com]
> Sent: Sunday, November 11, 2012 3:39 PM
> To: user@cassandra.apache.org
> Subject: Re: CREATE COLUMNFAMILY
>
> Also most idomatic clients use the information so they can return the
> appro
at by adding
metadata for foo. Will this work?
From: aaron morton [mailto:aa...@thelastpickle.com]
Sent: Sunday, November 11, 2012 3:39 PM
To: user@cassandra.apache.org
Subject: Re: CREATE COLUMNFAMILY
Also most idomatic clients use the information so they can return the
appropriate type t
ember 11, 2012 9:37 AM
> To: user@cassandra.apache.org
> Subject: Re: CREATE COLUMNFAMILY
>
> If you supply metadata cassandra can use it for several things.
>
> 1) It validates data on insertion
> 2) Helps display the information in human readable formats in tools like the
> C
...@gmail.com]
Sent: Sunday, November 11, 2012 9:37 AM
To: user@cassandra.apache.org
Subject: Re: CREATE COLUMNFAMILY
If you supply metadata cassandra can use it for several things.
1) It validates data on insertion
2) Helps display the information in human readable formats in tools like the
CLI and
then integer
4) columns in rows are sorted by the column name, strings sort
differently then integers
On Sat, Nov 10, 2012 at 11:55 PM, Kevin Burton wrote:
> I am sure this has been asked before but what is the purpose of entering
> key/value or more correctly key name/data type values on the
You've set a comparator for the super column names, but not the sub columns.
e.g.
[default@dev] set data['31']['address']['city']='noida';
org.apache.cassandra.db.marshal.MarshalException: cannot parse 'city' as hex
bytes
[default@dev] set data['31']['address'][utf8('city')]='noida';
Value
I understand that I might be missing something on my end. But somehow I cannot
get this working using Cassandra-cli:
[default@key1] create column family supusers with comparator=UTF8Type and
default_validation_class=UTF8Type and key_validation_class=UTF8Type and
column_type=Super;
59e2e950-9bd