On Mar 7, 2014, at 11:02 AM, Alan Gauld wrote:
GOT IT!! Finally! Thanks for all of your help!!
This is what I got, not sure if it’s correct but it’s working!
def print_hints(secret, guess):
if guess < 1 or guess > 100:
print
print "Out of range!"
print
if gues
On Mar 8, 2014, at 7:29 AM, eryksun wrote:
> i.e.
>
>guess < 1 or guess > 100
>
> becomes
>
>not not (guess < 1 or guess > 100)
Why a not not? Wouldn’t that just be saying do this because the second not is
undoing the first?
>
> distribute over the disjunction
>
>not (not (gue
On Mar 8, 2014, at 7:35 AM, Mark Lawrence wrote:
>
> I have no interest in the efficiency, only what is easiest for me to read,
> which in this case is the chained comparison. As a rule of thumb I'd also
> prefer it to be logically correct :)
>
What exactly is ment by a chained comparison?
On Mar 10, 2014, at 4:15 AM, eryksun wrote:
>
> Different strokes for different folks. I like to tinker with and
> disassemble things as I'm learning about them. I would have been
> ecstatic about open source as a kid. I learn simultaneously from the
> top down and bottom up -- outside to inside
>> On Mar 8, 2014, at 3:57 AM, spir wrote:
>>>
>>> Well done.
>>> And now that you have the right set of tests you can
>>> half the number of lines by combining your if
>>> conditions again, like you had in the original
>>> post. ie. Bring your hot/cold/warm tests together.
So below is what I fi
On Mar 10, 2014, at 8:52 PM, Ben Finney wrote:
>
> What does the Python interactive prompt display when you first launch an
> interactive Python shell?
Python 2.7.6 (v2.7.6:3a1db0d2747e, Nov 10 2013, 00:42:54)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "copyright", "credits" or
On Mar 10, 2014, at 8:52 PM, Ben Finney wrote:
>
> What does the Python interactive prompt display when you first launch an
> interactive Python shell?
Python 2.7.6 (v2.7.6:3a1db0d2747e, Nov 10 2013, 00:42:54)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "copyright", "credits" or
On Mar 8, 2014, at 11:50 AM, Scott dunning wrote:
>>>
>>> And now that you have the right set of tests you can
>>> half the number of lines by combining your if
>>> conditions again, like you had in the original
>>> post. ie. Bring your hot/cold/warm
On Mar 10, 2014, at 11:18 PM, Dave Angel wrote:
> Scott W Dunning Wrote in message:
>>
>
> Would you please stop posting in html?
I don’t know what you mean? I just use the text for my email provider. It’s
not html? I types up the code I ha
On Mar 10, 2014, at 11:18 PM, Dave Angel wrote:
Where are you guys using the forum? Through google? I was using that at first
but someone complained about something that google does and told me to get it
through my email. That’s what I’m doing now and I get bombarded with about 500
emails
On Mar 11, 2014, at 1:49 AM, Alan Gauld wrote:
>
> Not from the tutor list though. It only has a few
> mails normally - less than 50 most days.
>
Actually now that you say that most of the emails are coming through the reg
python-lists, not the tutor section. I guess I should just unsubscribe
On Mar 11, 2014, at 7:50 PM, William Ray Wing wrote:
>
> Simple. In Mail Preferences -> Composing -> Message Format -> Plain Text
> (Your setting is probably currently Rich Text.)
>
Got it, hopefully that helps.
___
Tutor maillist - Tutor@python
!!!
Scott
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
On Mar 28, 2014, at 9:54 PM, Scott W Dunning wrote:
> Hello, I’m working on some practice exercises from my homework and I’m having
> some issues figuring out what is wanted.
>
> We’re working with the while loop and this is what the question states;
>
> Write a fun
t the string `s`, `n` times.
This is also in the exercises and I’m not sure what it means and why it’s there.
assert isinstance(s, str)
assert isinstance(n, int)
Any help is greatly appreciated!
Scott
___
Tutor maillist - Tutor@python.org
To
I’m working on a few exercises and I’m a little stuck on this one.
This is what the book has but it just gives me an endless loop.
def square_root(a, eps=1e-6):
while True:
print x
y = (x + a/x) / 2
if abs(y-x) < epsilon:
On Mar 31, 2014, at 7:10 PM, Danny Yoo wrote:
Thanks for the info Danny! I’ll try that and I should be able to figure it out
with your help!
The book I was referring to is greentreepress.
___
Tutor maillist - Tutor@python.org
To unsubscribe or c
l for now while
compile my other questions you guys can hopefully help to shed light on.
Thanks for any help!!
Scott
___
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
https://mail.python.org/mailman/listinfo/tutor
On May 1, 2014, at 5:30 AM, Steven D'Aprano wrote:
Awesome, thanks everyone! I understand lists a lot better now.
I have another question. I don’t understand why below would give an error?
>>> greeting = 'Hello World’
>>> greeting [len(greeting)]
_
On May 5, 2014, at 10:13 PM, meenu ravi wrote:
> Likewise, the index of d, which is the last word in the word "Hello world" is
> 10.
>
> So, the maximum index you can access in the word "Hello world" is 10. But
> when you try to give the command,
>
> >>> greeting [len(greeting)]
>
> It is t
Hey guys I was hoping someone could tell me how to opted out of this list? I
have it going to two email addresses for some reason and I unsubscribed but
nothing happened. Any help is greatly appreciated!
Thanks,
Scott
___
Tutor maillist
Mac OS 10.10
Python 3.4.3
I self-study Python and am using it for a Coursera algorithm class.
Hi! My script sorts correctly on all my test arrays. My accumulator variable
to count the number of comparisons returns nonsense. I'm counting the (length
- one) of each sublist that will be sorted in
not working in Quick Sort script
To: tutor@python.org
Date: Thursday, October 29, 2015, 9:12 PM
On 29/10/15 19:11, Patti
Scott via Tutor wrote:
Caveat: I didn't check the algorithms for
correctness,
I'll just take your word
for that.
> My
accumulator variable to cou
newpath = find_path(graph, node, end, path)
if newpath: return newpath
return None
def find_all_paths(graph, start, end, path=[]):
path = path + [start]
if start == end:
return [path]
if not graph.has_key(start):
return []
I solved the question thanks to Alan's suggestions.
Attached is the .py file I ran to solve my question. Thanks guys.
On Sat, Nov 23, 2013 at 8:41 PM, Randolph Scott-McLaughlin II <
randolph.michael...@gmail.com> wrote:
> So I cleaned up the code to make it readable. I'm n
201 - 225 of 225 matches
Mail list logo