my script is
#!/usr/bin/env python
import datetime
import subprocess
import sys
import os
import signal
from time import sleep
def runForAWhile(cmd, secs=10):
print("running %s" % cmd)
timeout = datetime.timedelta(seconds=secs)
print timeout
proc = subprocess.Popen(cmd, stdout=subprocess.
ing 128.224.165.20 -c 4"
runForAWhile(cmd,30)
I see that "status" always "!=0“ why program is NOT exited
Lei
On Sun, Dec 19, 2010 at 1:15 AM, Alan Gauld wrote:
>
> "lei yang" wrote
>
>> def runForAWhile(cmd, secs=10):
>> proc = subp
On Sun, Dec 19, 2010 at 4:57 PM, Alan Gauld wrote:
>
> "lei yang" wrote
>
>
> def runForAWhile(cmd, secs=10):
> print("running %s" % cmd)
> timeout = datetime.timedelta(seconds=secs)
> print timeout
> proc = subprocess.Popen(cmd, stdout=sub
..@10.0.0.1"
host_run(cmd,10)
if cmd="ssh r...@10.0.0.1"
it never print "hello i'm here" , how can i handle this issue, and I
find my script cant process the "timeout" to kill it.
if cmd="ping 128.114.122.2", no this issue.
Lei
On Sun, Dec 19, 2010
t. I don't know
why.
my script is to run a cmd, if more than 10 sec, kill it
can you show me where is wrong, thanks in advance
Lei
> So my guess is, your script gets stuck at that line.
> But if you ctrl-C to stop the script, you should see where your program gets
> stuck. You di
tuck. That would be a very
> important first step for debugging.
>
> And if I run this script, I get the following:
> "
> $> python bla.py
> running ssh r...@10.0.0.1
> ssh: connect to host 10.0.0.1 port 22: Connection refused
>
> hello,i'm here
&
sh r...@10.0.0.1
>>> for you?
>>>
>>
>> [lya...@pek-lpgbuild13 py]$ ssh r...@10.0.0.1
>> ssh: connect to host 10.0.0.1 port 22: Connection timed out
>>
>> but it will wait for above 30 seconds then print "ssh: connect to host
>> 10.0.0.1
On Sun, Dec 19, 2010 at 9:05 PM, Sander Sweers wrote:
> On 19 December 2010 13:43, lei yang wrote:
>> Right, it gets stuck at the readline(), is there a function not get
>> stuck to instead of readline().
>
> readline() will keep reading stdout until it received a newli
On Sun, Dec 19, 2010 at 9:05 PM, Sander Sweers wrote:
> On 19 December 2010 13:43, lei yang wrote:
>> Right, it gets stuck at the readline(), is there a function not get
>> stuck to instead of readline().
>
> readline() will keep reading stdout until it received a newli
>>>start_time = "2014-7-1"
>>> revlines = commands.getoutput("git log --pretty=format:'%ad:%an'
--date=short --since='%s' --no-merges" %start_time).strip().split('\n')
Traceback (most recent call last):
File "", line 1, in
ValueError: unsupported format character 'a' (0x61) at index 26
>>>
if
Hi experts
I have a function will print PASS status
def print_pass(t_elapsed):
"""
Print PASS to stdout with PASS (green) color.
"""
print_stdout(bcolors.PASS + "PASS" + bcolors.ENDC + " (%.2f s)" % t_elapsed)
I want to calculate the pass number, so I want to get " how many tim
Hi expert,
I want to use pexpect to send "ctrl+a+c"
how should I do?
self.vm_session.sendline("")
how to fill ???
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thanks, it works for me
Lei
On Wed, Jan 22, 2014 at 10:35 PM, eryksun wrote:
> On Wed, Jan 22, 2014 at 8:49 AM, lei yang wrote:
> >
> > I want to use pexpect to send "ctrl+a+c"
>
> What's ctrl+a+c? If this is for screen, then I think you mean ctrl+a c:
&g
Hi expert,
How to express shift+enter in python ?
Thanks
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Hi Chris,
I just use "xlwt" lib to newline in one cell, I find it display with one
line in windows but works in linux, so I guess it maybe"shift+enter" to
newline
Lei
On Sun, Sep 28, 2014 at 11:04 PM, Chris “Kwpolska” Warrick <
kwpol...@gmail.com> wrote:
> On Sun,
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