[Tutor] trouble with stringio function in python 3.2

Hello, My python code needs to run on versions 2.7 to 3.4. To use stringio function as appropriate, the code i use is; if sys.version < '3': dictionary = io.StringIO(u"""\n""".join(english_words)) else: dictionary = io.StringIO("""\n""".join(english_words)) The co

Re: [Tutor] trouble with stringio function in python 3.2

> On May 4, 2015 2:17 AM, "anupama srinivas murthy" < > anupama.2312.bm...@gmail.com> wrote: > >> Hello, >> >> My python code needs to run on versions 2.7 to 3.4. To use stringio >> function as appropriate, the code i use is; >> >> if

Re: [Tutor] Query regarding output

for a[x] in a: print(a) Except for when x = 0, a[x] never takes on its original value throughout the iterations So for x = 0, we get: [0, 1, 2, 3] [1, 1, 2, 3] [2, 1, 2, 3] [3, 1, 2, 3] For x = 1: [0, 0, 2, 3] [0, 0, 2, 3] [0, 2, 2, 3] [0, 3, 2, 3] For x = 2: [0, 1, 0, 3] [0, 1, 1, 3] [0, 1