Is there a way to write an if statement that will pick up duplicates (two ‘1’s):
L = ['1', '4', '1']
if (L[0]) != (L[1]) != (L[2]):
print "THEY ARE NOT EQUAL"
else:
print "THEY ARE EQUAL"
When I run this code, it prints “THEY ARE NOT EQUAL” when it should print the
else “THEY ARE EQUAL”.
I am kind of stuck on what is probably a simple thing:
If we have a file of words like this:
“first”,”word”,”in”,”that”,”another”,”part”,”of”,”this”
f = open('words.txt', "r")
words = f.read()
will read the whole file, is there a way to read just the words: first word in
that another part
Python version = 2.7.1
Platform = win32
I am kind of stuck on what is probably a simple thing:
If we have a file of words like this:
“first”,”word”,”in”,”that”,”another”,”part”,”of”,”this”
f = open('words.txt', "r")
words = f.read()
will read the whole file, is there a way to read just the
I am just wondering if anyone can explain how the return statement in this
function is working (the code is from activestate.com)? Where does x come from
– it is not initialized anywhere else and then just appears in the return
statement. Any help would be appreciated.
def primes(n):
"""Pr
Can anyone tell me what I am doing wrong here. When trying to call the factors
function from main with x = factors(Tn), getting the error message: “TypeError:
'int' object is not callable”? Any help would be appreciated. Thanks.
def factors(n):
L = []
for i in range(1, int(n ** 0.5) + 1
I’m trying to sort a list of tuples based on the second item in the tuple. When
I run this in IDLE I get the correct output; however, when running inside of a
program, and calling the counter() function, sorted does not seem to work? Any
ideas on why this works in IDLE and not in program would b
