please im new to python or any other programming language. please i want to
understand how slicing works
[start,stop,step]
>>> 'abc'[0:3]
'abc'
>>>'abc'[0:-1]
'ab'
why does 'abc'[2:1] or 'abc'[2:1] print ' ' instead of 'c'???
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Tutor maillist
I read through some documentations yesterday after posting.
I will share what I think. There are three parts to matplotlib: backend,
artist, and scripting. The artist layer is the only one that really matters
for matplotlib users.
Why haven't the developers fixed the problem? Considering Python's
many systems are constrained by history. matplotlib started when the vile (yes,
thats just a personal opinion) matlab proved too cumbersome and someone decided
to try again in python... but knowing matlab, he picked up ideas from there.
since then all kinds of stuff has been bolted on. it's powe
On 15/06/18 14:57, kenneth yashim wrote:
> please im new to python or any other programming language. please i want to
> understand how slicing works
>
> [start,stop,step]
>
'abc'[0:3]
> 'abc'
>
'abc'[0:-1]
> 'ab'
>
> why does 'abc'[2:1] or 'abc'[2:1] print ' ' instead of 'c'???
On 15/06/18 17:35, C W wrote:
> Why haven't the developers fixed the problem?
This is open source, developed by volunteers to
meet their own needs primarily and others by
happy coincidence.
If the existing solution meets the needs of the
developers they have no incentive to spend time
to "fix"
On Fri, Jun 15, 2018 at 04:57:47PM +0300, kenneth yashim wrote:
> please im new to python or any other programming language. please i want to
> understand how slicing works
>
> [start,stop,step]
>
> >>> 'abc'[0:3]
> 'abc'
>
> >>>'abc'[0:-1]
> 'ab'
>
> why does 'abc'[2:1] or 'abc'[2:1] prin
On Fri, Jun 15, 2018 at 12:35:36PM -0400, C W wrote:
> Why haven't the developers fixed the problem?
matplotlib is free, open source software. If volunteers don't "fix the
problem", who is paying for the work to be done?
Are you volunteering?
Or willing to pay somebody to do the work? $30,000
