"bob gailer" wrote
"Antonio de la Fuente" wrote
> if not line.isspace() and not line == 'foo':
> fileOut.write(line)
But then, the new log file will have all the blocks, even the ones that
had 'foo' on it, even if the foo lines weren't there anymore. No? or
is there anything that I don'
Hi ,
How do I run a python script using wsgi? I am not using any web
framework I just wish to try out running a simple script.
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Kent Johnson wrote:
On Mon, Nov 24, 2008 at 7:19 PM, Mike Meisner wrote:
> 3. A good GUI front end for creating the database, creating
forms for user
> data input, queries, reports, etc.
For this you might look at Dabo:
http://dabodev.com/
I haven't worked with it myself but some people
Humm. Most enlighting.
For my case the solution is clearly to have an initialization file. In
case the specified extension is not known then I'll prompt the user to
save the file and pass on the responsibility.
Txs everyone,
Miguel
_
On Wed, Nov 18, 2009 at 5:11 AM, Amit Sethi wrote:
> Hi ,
>
> How do I run a python script using wsgi? I am not using any web
> framework I just wish to try out running a simple script.
You need to run a WSGI-compliant server and configure it to host your
application. The std lib contains a simpl
I'm dealing with bigger lists than I have been, and noticed this is getting
really slow. Is there a faster way to do this?
for x in list1:
if x not in list2:
list3.append(x)
My search is taking up to 5 minutes to complete.
__
Do You
On Wed, Nov 18, 2009 at 1:51 PM, GoodPotatoes wrote:
> I'm dealing with bigger lists than I have been, and noticed this is getting
> really slow. Is there a faster way to do this?
>
> for x in list1:
> if x not in list2:
> list3.append(x)
>
> My search is taking up to 5 minutes to com
On Wed, Nov 18, 2009 at 4:51 PM, GoodPotatoes wrote:
> I'm dealing with bigger lists than I have been, and noticed this is getting
> really slow. Is there a faster way to do this?
>
> for x in list1:
> if x not in list2:
> list3.append(x)
>
> My search is taking up to 5 minutes to com
* Christian Witts [2009-11-18 09:53:15 +0200]:
> Date: Wed, 18 Nov 2009 09:53:15 +0200
> From: Christian Witts
> To: Antonio de la Fuente
> CC: Python Tutor mailing list
> Subject: Re: [Tutor] Introduction - log exercise
> User-Agent: Thunderbird 2.0.0.23 (X11/20090817)
> Message-ID: <4b03a7e.
On Wed, Nov 18, 2009, GoodPotatoes wrote:
>I'm dealing with bigger lists than I have been, and noticed this is getting
>really slow. Is there a faster way to do this?
>
>for x in list1:
>if x not in list2:
>list3.append(x)
>
>My search is taking up to 5 minutes to complete.
When I ha
On Wed, Nov 18, 2009 at 5:03 PM, Bill Campbell wrote:
>
> When I have had to deal with large lists, I have found that using
> an intermediate dictionary can save huge amounts of time.
> Something like:
>
> dict2 = {}.fromkeys(list2)
> for x in list1:
>if x not in dist2:
>d
On Wed, Nov 18, 2009 at 5:54 PM, Luke Paireepinart
wrote:
> This is really just a round-about way of using sets.
> I don't really want to give a code-sample unless he's confirmed he's not
> doing this as homework, but the set version is much more simple (shorter
> code that makes more sense) and e
* Antonio de la Fuente [2009-11-17 16:58:08 +]:
> Date: Tue, 17 Nov 2009 16:58:08 +
> From: Antonio de la Fuente
> To: Python Tutor mailing list
> Subject: [Tutor] Introduction - log exercise
> Organization: (muybien.org)
> User-Agent: Mutt/1.5.20 (2009-06-14)
> Message-ID: <20091117165
[Luke Paireepinart]
>> This is really just a round-about way of using sets.
>> I don't really want to give a code-sample unless he's confirmed he's not
>> doing this as homework, but the set version is much more simple (shorter
>> code that makes more sense) and extremely quick as well. If you're
"Tim Peters" wrote
result = set(list1) - set(list2)
Of course the result is a set then.
Which means that if there were duplicates in list1 you only get
one copy in the result. As Tim says, whether that is good, bad
or irrelevant depends on the problem context.
Maybe that will work fin
I have the following method:
def get_log_dates(the_date_we_want_data_for):
t = time.strptime(the_date_we_want_data_for, '%Y%m%d')
t2 = datetime.datetime(*t[:-2])
extra_day = datetime.timedelta(days=1)
t3 = t2 + extra_day
next_log_date = t3.strftime('%Y%m%d')
return (the_date_we_want_da
2009/11/5 Kent Johnson :
> On Thu, Nov 5, 2009 at 5:06 AM, Stephen Nelson-Smith
> wrote:
>> Hello,
>>
>> I want to make an HTTP POST which will require authentication.
>
> What kind of authentication? Basic auth is easy to use from Python;
> form-based auth is a bit tricker.
>
>> This is because
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