thanks!
On 11/11/05, Gregor Lingl <[EMAIL PROTECTED]> wrote:
> Liam Clarke schrieb:
>
> >Hi Shi,
> >
> >For what you're doing, nothing at all.
> >
> >When you use a colon, slice syntax, it defaults to [start:end] so p =
> >a[:] is the same as
> >p = a[0:len(a)]
> >
> >
> >
> But in fact there is a
> what is the difference between the two ways of assigning the list?
> p=a vs. p=a[:]
The first makes p point at the same list as a.
The second makes p point at a *copy* of the list pointed to by a.
You will see the difference if you try to modify the lists after assignment.
In the first case mod
Oooh... that's a gotcha. Shi Mu - did you understand that? There is a
crucial difference as Gregor pointed out, that I missed, and I do
apologise.
On 11/11/05, Gregor Lingl <[EMAIL PROTECTED]> wrote:
> Liam Clarke schrieb:
>
> >Hi Shi,
> >
> >For what you're doing, nothing at all.
> >
> >When you
Liam Clarke schrieb:
>Hi Shi,
>
>For what you're doing, nothing at all.
>
>When you use a colon, slice syntax, it defaults to [start:end] so p =
>a[:] is the same as
>p = a[0:len(a)]
>
>
>
But in fact there is a difference. I'll show you:
>>> a=range(5)### creates a list-object
>>> id(a)
Hi Shi,
For what you're doing, nothing at all.
When you use a colon, slice syntax, it defaults to [start:end] so p =
a[:] is the same as
p = a[0:len(a)]
Regards,
Liam Clarke
On 11/11/05, Shi Mu <[EMAIL PROTECTED]> wrote:
> what is the difference between the two ways of assigning the list?
> p=
thanks!
On 11/10/05, Liam Clarke <[EMAIL PROTECTED]> wrote:
> Hi Shi,
>
> For what you're doing, nothing at all.
>
> When you use a colon, slice syntax, it defaults to [start:end] so p =
> a[:] is the same as
> p = a[0:len(a)]
>
> Regards,
>
> Liam Clarke
>
> On 11/11/05, Shi Mu <[EMAIL PROTECTED]
