"Roelof Wobben" wrote
image = urllib.URLopener()
image.retrieve("http://www.pythonchallenge.com/pc/def/peak.html","banner.p";
)
Roelof,
Please do not post a series of request for help on each of the
Python Challenge puzzles. They are intended to be challenging
and to force you to consult t
On 12 October 2010 18:35, Roelof Wobben wrote:
> image = urllib.URLopener()
> image.retrieve("http://www.pythonchallenge.com/pc/def/peak.html","banner.p";
> )
>
OK firstly, image is an URLopener, so whatever URL you specify, that's the
file that it will download. (I would therefore suggest you
On Tue, Oct 12, 2010 at 1:35 PM, Roelof Wobben wrote:
>
>
> Hello,
>
> I have this code :
>
> import urllib
> import pickle
>
> image = urllib.URLopener()
> image.retrieve("http://www.pythonchallenge.com/pc/def/peak.html","banner.p";
> )
> plaatje = open("banner.p", "rb")
> plaatje2 = pickle.load
On 12/10/10 18:35, Roelof Wobben wrote:
Hello,
I have this code :
import urllib
import pickle
image = urllib.URLopener()
image.retrieve("http://www.pythonchallenge.com/pc/def/peak.html","banner.p"; )
plaatje = open("banner.p", "rb")
plaatje2 = pickle.load(plaatje)
But it gives this output :
Am 12.10.2010 19:35, schrieb Roelof Wobben:
Hello,
I have this code :
import urllib
import pickle
image = urllib.URLopener()
image.retrieve("http://www.pythonchallenge.com/pc/def/peak.html","banner.p"; )
plaatje = open("banner.p", "rb")
plaatje2 = pickle.load(plaatje)
But it gives this outp
