Fred said:
> >> Obviously, the lambda is using "value" at the end of the loop (4),
> >>rather than what I want, "value" during the loop (0,1,2,3).
Christian said:
> > Right. I think the issue is that your lambda calls another funtion.
> > However, the function isn't called until the lambda is c
> Just to be able to talk about things, let's give a name to the global
> namespace as: "G".
>
> Whenever we call a function, we build a new environment that's chained up
> to the one we're in at the time of function construction. This
> corresponds to what people's ideas of the "stack frame" is.
> The original solution does use a closure. The problem is that variables
> are not bound into a closure until the scope of the variable exits. That
> is why using a separate factory function works - the closure is bound
> when the factory function exits which happens each time through the
> loop.
Christian Wyglendowski wrote:
>>-Original Message-
>>From: [EMAIL PROTECTED]
>> If I have this code:
>> Obviously, the lambda is using "value" at the end of the loop (4),
>>rather than what I want, "value" during the loop (0,1,2,3).
>
> Right. I think the issue is that your lambda ca
def doLambda(val):
print "value 2:", val
commands = []
for value in range(5):
print "value 1:", value
commands.append(lambda:doLambda(value))
Close but not quite. Try:
commands.append(lambda v=value:doLambda(v))
value is a local variable in doLambda
>
> def doLambda(val):
>print "value 2:", val
>
> commands = []
> for value in range(5):
>print "value 1:", value
>commands.append(lambda:doLambda(value))
>
> for c in commands:
>c()
Hi Fred,
Ah, this one of those unfrequently asked questions.
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Fred Lionetti
> Sent: Wednesday, November 16, 2005 2:32 PM
> To: tutor@python.org
> Subject: [Tutor] lambda in a loop
>
> Hi everyone,
Hello,
> If I have this code:
>
> ---
