wow,
very interesting thread this was..I probably learnt a lot from this than by
flipping a few pages of a python text...
thank you all for your interesting responses ..
iyer
Luke Paireepinart <[EMAIL PROTECTED]> wrote:
On 6/18/07, Simon Hooper <[EMAIL PROTECTED]> wrote: Hi Luke,
* On 17/0
On 6/18/07, Simon Hooper <[EMAIL PROTECTED]> wrote:
Hi Luke,
* On 17/06/07, Luke Paireepinart wrote:
> a more expanded version that accounts for either list being the longer
> one, or both being the same length, would be:
>
> >>> if len(t) > len(l): x = len(t)
> else: x = len(l)
> >>> print [
Hi Luke,
* On 17/06/07, Luke Paireepinart wrote:
> a more expanded version that accounts for either list being the longer
> one, or both being the same length, would be:
>
> >>> if len(t) > len(l): x = len(t)
> else: x = len(l)
> >>> print [(l[i%len(l)],t[i%len(t)]) for i in range(x)]
> [(1, '
nb)
x = 10
print [(a[i%na], b[i%nb]) for i in range(x)], "- modulus (extended)"
print
print "==="
This mailing list is great. Thanks to all the experienced Python coders
who offer various solutions to the questions, and to all the beginners
who ask them.
On Jun 17, 2007, at 3:44 AM, John Fouhy wrote:
> On 17/06/07, Iyer <[EMAIL PROTECTED]> wrote:
>>
>> say, if I have a list l = [1,2,3,5]
>>
>> and another tuple t = ('r', 'g', 'b')
>>
>> Suppose I iterate over list l, and t at the same time, if I use
>> the zip
>> function as in zip(l,t) , I wil
"Luke Paireepinart" <[EMAIL PROTECTED]> wrote
> The first thing that occurred to me was just to use a modulus to
> index
> into the second, shorter list.
That was the first thing that occured to me too but when
I tried it I couldn't get it to work...
> >>> l = [1,2,3,4,5]
> >>> t = ('r','g','b
Alan Gauld wrote:
> "Iyer" <[EMAIL PROTECTED]> wrote
>
>
>> Any pythonic way to iterate over a sequence, while iterating
>> over another shorter sequence continously
>>
The first thing that occurred to me was just to use a modulus to index
into the second, shorter list.
>>> l = [1,2,3,4
"Iyer" <[EMAIL PROTECTED]> wrote
> Any pythonic way to iterate over a sequence, while iterating
> over another shorter sequence continously
I don;t know how pythonic it is, but I'd do it thus:
>>> a = (1, 2, 3, 4)
>>> b = ('a', 'b', 'c')
>>> n = len(a)/len(b) + 1
>>> t = map(None,a,b*n)[:len(
On 17/06/07, Iyer <[EMAIL PROTECTED]> wrote:
>
> say, if I have a list l = [1,2,3,5]
>
> and another tuple t = ('r', 'g', 'b')
>
> Suppose I iterate over list l, and t at the same time, if I use the zip
> function as in zip(l,t) , I will not be able to cover elements 3 and 5 in
> list l
>
> >>> l =
