On Wed, 29 Sep 2010 01:41:22 am Peter Otten wrote:
> You should never iterate over a list or dictionary and add or remove
> items to it at the same time. That is a recipe for disaster even if
> it doesn't fail explicitly*
[...]
> (*) I'll leave it to Steven D'Aprano to add the fine print ;)
I'l
On 9/28/2010 11:13 AM Norman Khine said...
ok, great.
one thing i wanted to ask is how could i extend the class so that i
can just change the name of the csv file?
Python provides for instance initialization with a class __init__
method, so you could modify your class as follows:
def sort
ok, great.
one thing i wanted to ask is how could i extend the class so that i
can just change the name of the csv file?
On Tue, Sep 28, 2010 at 6:53 PM, Emile van Sebille wrote:
> On 9/28/2010 9:37 AM Norman Khine said...
>>
>> thank you, here is the updated version:
>>
>> http://pastie.org/118
On 9/28/2010 9:37 AM Norman Khine said...
thank you, here is the updated version:
http://pastie.org/1186860
The only obvious redundancy is the duplicated sort of options just
before the return. You only need the newer sort_key based one.
Emile
___
thank you, here is the updated version:
http://pastie.org/1186860
On Tue, Sep 28, 2010 at 5:50 PM, Emile van Sebille wrote:
> On 9/28/2010 7:12 AM Norman Khine said...
>>
>> thanks for the reply, i think i have it now, perhaps it could be done
>> better
>>
>
> I think I'd use a helper function t
On 9/28/2010 7:12 AM Norman Khine said...
thanks for the reply, i think i have it now, perhaps it could be done better
I think I'd use a helper function to sort:
def sortOtherToEnd(val):
if val['name'] == 'other:
return ''
return val['name']
#then sort it
topics.sort(key=sortOth
Norman Khine wrote:
> thanks for the reply, i think i have it now, perhaps it could be done
> better
> >>> topics.sort(key=itemgetter('name'))
> >>> for i, t in enumerate(topics):
> ... for (k, v) in t.iteritems():
> ... if v == 'other':
> ... topics.append(top
thanks for the reply, i think i have it now, perhaps it could be done better
http://pastie.org/1186545
On Tue, Sep 28, 2010 at 2:56 PM, Emile van Sebille wrote:
> Hi Norman,
>
> Read my reply again -- that's the second question I answered.
>
> Emile
>
>
> On 9/28/2010 12:56 AM Norman Khine said
thanks for the reply. i should have been more specific in my question ;)
the order in which 'other' is listed is not always the last item of
the list as it is dependent on where in the CSV file it is included.
what i was trying to do is to take create the list of dictionary items
and then find th
On 9/27/2010 1:22 PM Norman Khine said...
what is the correct way to ensure that {'industry': 'travel', 'name':
'other','value': MSG(u"Other")} is always added to the end of this
list after all the items have been sorted?
here is the code which returns this list:
options.sort(key=itemgette
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