On 05/11/17 15:05, Atux Atux wrote:
> ok then. how do i link 'r' to remove an item from right with mylist.pop(0)
> and how can i remove an item from left with '0r'?
Same way you detected the 'q' to quit.
Using a variation of the 'code' I sent earlier:
response = input().lower() # allow user s
ok then. how do i link 'r' to remove an item from right with mylist.pop(0)
and how can i remove an item from left with '0r'?
On Sun, Nov 5, 2017 at 11:27 AM, Steven D'Aprano
wrote:
> On Sun, Nov 05, 2017 at 10:07:31AM +0200, Atux Atux wrote:
> > Hi. Thanks a lot for the replies. i am actually nw
On Sun, Nov 05, 2017 at 10:07:31AM +0200, Atux Atux wrote:
> Hi. Thanks a lot for the replies. i am actually nw to programming as well.
> your code keeps asking the user for a number and puts it to the end. how
> can i make it to add a number at the beginning if the user adds 01, then
> the program
Hi. Thanks a lot for the replies. i am actually nw to programming as well.
your code keeps asking the user for a number and puts it to the end. how
can i make it to add a number at the beginning if the user adds 01, then
the program it will strip 0 and add 1 at ythe beginning, please?
John
On Su
Hello and welcome duplicative Atux,
>i am new to the area and i am struggling with a small project that i have.
>i need some help please.
New to Python, perhaps. New to programming, as well?
>i need to create a program that runs constantly unless the user
>presses q to end it.
This is a good
On Sat, Nov 04, 2017 at 10:11:08PM +0200, Atux Atux wrote:
[...]
> i got the starting point where it asks the user and goes until 'q' is
> pressed.
>
> while True:
> if input("\n\n\nType a number to add it to the queue or q to
> exit: ") == 'q':
> break
>
> but i a stuck on how to c
On 04/11/17 20:11, Atux Atux wrote:
> i am new to the area and i am struggling with a small project that i have.
You are on the right path.
When faced with any software project you have to keep breaking it down
till you get to something you can write.
You've made a start, lets see what else needs
