On Sun, Sep 21, 2008 at 2:17 PM, Dinesh B Vadhia
<[EMAIL PROTECTED]> wrote:
> Given a (numpy) array how do you create a dictionary of lists where the list
> contains the column indexes of non-zero elements and the dictionary key is
> the row index. The easy way is 2 for loops ie.
>
> import numpy
help.
Dinesh
Message: 5
Date: Sun, 21 Sep 2008 09:15:00 +0100
From: "Alan Gauld" <[EMAIL PROTECTED]>
Subject: Re: [Tutor] array and dictionary
To: tutor@python.org
Message-ID: <[EMAIL PROTECTED]>
Content-Type: text/plain; format=flowed; charset="iso-8859-1";
r
"Dinesh B Vadhia" <[EMAIL PROTECTED]> wrote
Hi! Say, I've got a numpy array/matrix of the form:
[[1 6 1 2 3]
[4 5 4 7 0]...
[2 1 0 5 6]]
I want to create a dictionary of rows (as the keys) mapped
to lists of non-zero numbers in that row
Caveat, I dont know about numpy arrays.But assuming
Straight forward method would be...
>>> a=[[1],[2]]
>>> b={}
>>> for x in range(len(a)):
... b[x] = a[x]
...
>>> a
[[1], [2]]
>>> b
{0: [1], 1: [2]}
>>>
regards,
shantanoo
On 21-Sep-08, at 11:36 AM, Dinesh B Vadhia wrote:
Hi! Say, I've got a numpy array/matrix of the form:
[[1 6 1 2 3]
