On Sat, Sep 1, 2012 at 3:18 AM, Dave Angel wrote:
>
> Somehow i missed the point that xrange() is NOT necessarily limited to
> Python int values. So it may be usable on your machine, if your Python
> is 64bit. All I really know is that it works on mine (2.7 64bit, on
> Linux). See the following qu
On 08/31/2012 09:08 PM, Scurvy Scott wrote:
> First of all thank you guys for all your help. The manual is really no
> substitute for having things explained in laymans terms as opposed to a
> technical manual.
>
> My question is this- I've been trying for a month to generate a list of all
> pos
I'm not sure what the point of any of that is; you're making a simple
> problem complex. If you're wanting to accomplish the task without using
> any of the itertools stuff, why not just:
>
>
> current = 10**9
> lim = 10**10
> while current < lim:
> print current #or write to file, or wha
I could comment this better.
We have a function, iterToHighNum, that takes two parameters: increment and
high_num.
increment is how long the list of numbers being added to the old increment
list of ints, to create a shorter int list that maintains the sequential
count, looking for the high number
On 09/01/2012 01:46 AM, Dwight Hutto wrote:
> Here's the better function fixed with a return statement I forgot, but
> might not be as quick as the pre-built functions already shown:
>
> def iterToHighNum(increment,high_num):
> end_point = 0
> a = [i for i in range(0,increment)]
> while
Here's the better function fixed with a return statement I forgot, but
might not be as quick as the pre-built functions already shown:
def iterToHighNum(increment,high_num):
end_point = 0
a = [i for i in range(0,increment)]
while (end_point != high_num) == True:
for integer in
It might be a little buggy, but I'm in a rush, so it has a flaw in it. But
I think you get the point I'm trying to make.
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I mean line 7.
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You can also watch this happen by uncommenting print on line 8:
def iterToHighNum(increment,high_
num):
end_point = 0
a = [i for i in range(0,increment)]
while (end_point != high_num) == True:
for integer in a:
if integer != high_num:
print "no matc
On Sat, Sep 1, 2012 at 12:29 AM, Scurvy Scott wrote:
>
> The while loop works for simply printing. Now I'm trying to save to a file
>
> I = 10
> Boogers = raw_input("file")
> Baseball = open(Boogers)
As ASCII, that's 11 bytes per number times 9 billion numbers. That's
approximately 92 GiB
Dear Scurvy,
I don't know if this has been suggested yet, but I just broke the
larger list of 10 digit nums into segments, and at the end of the loop,
kept the previous last num in the segment as the beginning of the next
range() that goes through the same amount of ints in each segmentation of
On 08/31/2012 10:38 PM, Scurvy Scott wrote:
> Now I've got
>
> A = 10
> I = raw_input("file name> ")
> TheFile = open(I, 'w')
>
> TheFile.truncate
> def allten(a):
> while a < 99:
> a = + 1
> TheFile.write(a)
> allten(a)
>
> The result is:
> Open file 'file.t
On 08/31/2012 10:14 PM, Scurvy Scott wrote:
> Thanks for the reply. This isn't an assignment per se as I'm just learning
> python for my own sake- not in classes or school or what have you. As I said
> I'm pretty new to python picking up whatever I can and generators are
> something that I haven
On Fri, Aug 31, 2012 at 9:08 PM, Scurvy Scott wrote:
>
> My question is this- I've been trying for a month to generate a list of
> all possible 10 digit numbers. I've googled, looked on stackoverflow,
> experimented with itertools,
In itertools, look at count() and islice(). An alternative to isl
On 08/31/2012 09:08 PM, Scurvy Scott wrote:
> First of all thank you guys for all your help. The manual is really no
> substitute for having things explained in laymans terms as opposed to a
> technical manual.
>
> My question is this- I've been trying for a month to generate a list of all
> pos
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