On 06/14/2018 05:01 AM, Deepak Dixit wrote:
> Thanks a lot for this information.
>
> On Thu, Jun 14, 2018, 4:28 PM Alan Gauld via Tutor wrote:
>> Yes, the default argument object is created when the
>> function is defined (ie before it is even called the
>> first time) and the same reference to
Thanks a lot for this information.
On Thu, Jun 14, 2018, 4:28 PM Alan Gauld via Tutor wrote:
> On 14/06/18 08:40, Deepak Dixit wrote:
> > You mean that for default args and passed args of mutable type, python
> uses
> > different object and same reference will be used for further calling of
> th
On 14/06/18 08:40, Deepak Dixit wrote:
> You mean that for default args and passed args of mutable type, python uses
> different object and same reference will be used for further calling of the
> function.
Yes, the default argument object is created when the
function is defined (ie before it is e
You mean that for default args and passed args of mutable type, python uses
different object and same reference will be used for further calling of the
function.
Now one more thing I want to ask you that how can I get deep understanding
of python like how list, dictionary works internally and other
On 14/06/18 08:04, Deepak Dixit wrote:
> def test2(nums=[]):
> nums.append(len(nums));
> return nums
>
> print 'test2()', test2()
> print 'test2([1,2,3])', test2([1,2,3])
> print 'test2([1,2])', test2([1,2])
> print 'test2()', test2()
> print 'test2()', test2()
>
> Calling test2
