On Wed, May 07, 2014 at 08:49:11PM -0700, Scott W Dunning wrote:
[...]
> > >>> greeting [len(greeting)]
> >
> > It is trying to access the character at the position "11", where the
> > string "Hello world" doesn't contain any value in the index "11" and
> > the maximum index is 10. So it throws
On Wed, May 7, 2014 at 8:49 PM, Scott W Dunning wrote:
>
> On May 5, 2014, at 10:13 PM, meenu ravi wrote:
>
>> Likewise, the index of d, which is the last word in the word "Hello world"
>> is 10.
>>
>> So, the maximum index you can access in the word "Hello world" is 10. But
>> when you try to
On May 5, 2014, at 10:13 PM, meenu ravi wrote:
> Likewise, the index of d, which is the last word in the word "Hello world" is
> 10.
>
> So, the maximum index you can access in the word "Hello world" is 10. But
> when you try to give the command,
>
> >>> greeting [len(greeting)]
>
> It is t
On Tue, May 06, 2014 at 06:36:21PM +0100, Alan Gauld wrote:
> Aside:
> len() does work with range() and slicing so you can write
>
> myList[:len(mylist)]
>
> to get a copy of your list...
Even easier is a blank slice. The start defaults to zero, the
end to the length of the sequence, and the s
On 06/05/14 04:43, Scott Dunning wrote:
I have another question. I don’t understand why below would give an error?
greeting = 'Hello World'
greeting [len(greeting)]
Because list indexing starts at zero but len() returns the actual
length. So the last element of a list is
mylist[len(mylis
On Mon, May 5, 2014 at 9:04 PM, Scott W Dunning wrote:
>
> On May 1, 2014, at 5:30 AM, Steven D'Aprano wrote:
>
> Awesome, thanks everyone! I understand lists a lot better now.
>
> I have another question. I don’t understand why below would give an error?
>
greeting = 'Hello World’
On May 1, 2014, at 5:30 AM, Steven D'Aprano wrote:
>
Awesome, thanks everyone! I understand lists a lot better now.
I have another question. I don’t understand why below would give an error?
>>> greeting = 'Hello World'
>>> greeting [len(greeting)]
__
Hi Scott,
The variable greeting is of type "string".
>>> greeting = "Hello world"
>>> type(greeting)
The len(string) will count each character in the value of variable
"greeting" starting from '1'.
H - 1
e - 2
l - 3
l - 4
0 - 5
space - 6(Space and special characters are also counted)
On May 1, 2014, at 5:30 AM, Steven D'Aprano wrote:
Awesome, thanks everyone! I understand lists a lot better now.
I have another question. I don’t understand why below would give an error?
>>> greeting = 'Hello World’
>>> greeting [len(greeting)]
_
> The ouput for below is 2 when it seems like there should be 3 lists located
> inside x. Is it [10,20] that is not consider inside of x?Any tips on how
> to tell how to spot them more clearly?
>
> x = ['a', [2.0, 5, [10, 20]]]
> print len(x)
Hey Scott
Here, it looks like x is a list cont
On 01/05/2014 06:21, Scott W Dunning wrote:
Hello, I am new to python and have a final review coming up and was hoping you
could help me answer a few questions I came across while studying.
So, I get a little confused about lists sometimes. This one is a little hard
to make heads or tails of.
On Wed, Apr 30, 2014 at 10:21:41PM -0700, Scott W Dunning wrote:
> So, I get a little confused about lists sometimes. This one is a
> little hard to make heads or tails of. I get confused about how to
> tell how many lists are within one list like the one below. How many
> lists are located
On Thu, May 1, 2014 at 7:21 AM, Scott W Dunning wrote:
> Hello, I am new to python and have a final review coming up and was hoping
> you could help me answer a few questions I came across while studying.
>
>
> So, I get a little confused about lists sometimes. This one is a little hard
> to ma
13 matches
Mail list logo