> > isHTML = [filename if filename.endswith('.htm') or\
> >filename.endswith(.html') for filename in files]
> > return isHTML
>
> No, it should be...
Well spotted, but...
>
> isHTML = [filename for filename in files if
filename.endswith('.htm') or\
> filename.endswith('.html') for filenam
> > I am fine tuning list comprehensions (at least my understandng
> > thereof), and I'm not near a Python interpreter at the moment, so
I
> > was wondering if someone could tell me if I did OK -
> > def approachB(files):
> >
> > isHTML = [filename if filename.endswith('.htm') or\
> >filename.
Kent Johnson wrote:
Liam Clarke wrote:
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files:
>> def approachB(files):
>>
>> isHTML = [filename if filename.endswith('.htm') or\
>>filename.endswith(.html') for filename in files]
>> return isHTML
>
> No, it should be...
>
> isHTML = [filename for filename in files if
> filename.endswith('.htm') or\
> filename.endswith('.html') for
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files:
if filename.endswith('.htm') or filename.endswith('
Liam Clarke wrote:
Hello,
I am fine tuning list comprehensions (at least my understandng
thereof), and I'm not near a Python interpreter at the moment, so I
was wondering if someone could tell me if I did OK -
def approachA(files):
isHTML = []
for filename in files: