I always slice the string in this sort of situation:
s = "12345678901234567890123456789012 "
t = s[:10],s[10:20],s[20:-1]
print t
('1234567890', '1234567890', '123456789012')
One could always bracket it to make a list or whatever.
Hope this helps!
On 4/11/06, Paul Kraus <[EMAIL PROTECT
> Python regex is a bit more verbose than Perl but you can do the same thing:
>
> In [2]: import re
>
> In [11]: m=re.match("(.{10})(.{10})(.{13})", line)
>
> In [13]: m.group(1, 2, 3)
> Out[13]: ('1234567890', '1234567890', '123456789012 ')
That work great. Regex tend to be "expensive" is there a
Paul Kraus wrote:
> Ok sorry for the perl refernce but I can't figure out how to do this.
> I have a fixed width text file i need to parse.
>
> so lets say I want an array to containt the pieces i need.
> if the fields I want are lengths from left to right.
> 10 10 13
> 123456789012345678901234567
Ok sorry for the perl refernce but I can't figure out how to do this.
I have a fixed width text file i need to parse.
so lets say I want an array to containt the pieces i need.
if the fields I want are lengths from left to right.
10 10 13
12345678901234567890123456789012
I want to turn this into a
