prasad rao wrote:
hi
I got it right.
>>> z=[]
>>> for x in range(1000):
if divmod(x,3)[1]==0:z.append(x)
if divmod(x,5)[1]==0:z.append(x)
>>> sum(set(z))
233168
Instead of using the set function you could just use an elif in your for
loop.
>>> z=[]
>>> for x in range(1000):
On Sun, Jan 4, 2009 at 14:18, prasad rao wrote:
z=[]
for x in range(1000):
> if divmod(x,3)[1]==0:z.append(x)
> if divmod(x,5)[1]==0:z.append(x)
sum(set(z))
> 233168
This can be done in one line of python.
>>> sum([x for x in range(1000) if x %3 == 0 or x % 5 == 0])
233168
Greets
hi I got it right.
>>> z=[]
>>> for x in range(1000):
if divmod(x,3)[1]==0:z.append(x)
if divmod(x,5)[1]==0:z.append(x)
>>> sum(set(z))
233168
I am sorry if this is outside the perimeter of this list.
___
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On Sat, Dec 27, 2008 at 3:42 AM, Alan Gauld wrote:
>
> Its C rather than C++.
> The <> in include statements are a variation on the "" which can also be
> used.
> The differences are subtle and have to do with the search path I think. But
> its
> been so long since I did serious C/++ I can't recal
"prasad rao" wrote
http://svn.python.org/view/python/trunk/Objects/listobject.c?rev=67498&view=markup
Kent ! This is grek and latin to me.From the presence of header
files it
looks C++.But headerfiles are not between '<' and '>' .
Its C rather than C++.
The <> in include statements are
Thanks for help.
>
http://svn.python.org/view/python/trunk/Objects/listobject.c?rev=67498&view=markup
Kent ! This is grek and latin to me.From the presence of header files it
looks C++.But headerfiles are not between '<' and '>' .
>But why are you trying to sort in this fashion?
Alan Gauld!
