l would not strip out the charecter...I
may try a bit harder to make it work just becouse it bugs me that you made
it work.
Thanks again
John Ertl
-Original Message-
From: Kent Johnson
Cc: tutor@python.org
Sent: 3/27/05 2:31 PM
Subject: Re: [Tutor] re question
Jacob S. wrote:
> Kent
Jacob S. wrote:
Kent -- when pulling out just the numbers, why go to the trouble of
splitting by "," first?
Good question. It made sense at the time :-)
Here is another way using re.findall():
>>> import re
>>> s='Std Lvl: 850hPa, 1503m, 16.8C, 15.7C, 205 @ 11kts'
>>> re.findall(r'[\d\.]
Kent -- when pulling out just the numbers, why go to the trouble of
splitting by "," first?
import re
pat = re.compile(r"[^\d.]*")
t = """SigWind: 857hPa, , 21.0C, 20.1C, 210 @ 9kts
SigWind: 850hPa±, , , , 205 @ 11kts
Std Lvl: 850hPa, 1503m, 16.8C, 15.7C,
I don't know why this isn't working for you but this worked for me at a DOS
console:
>>> s='850hPa±'
>>> s
'850hPa\xf1'
>>> import re
>>> re.sub('\xf1', '*', s)
'850hPa*'
>>> import sys
>>> sys.stdout.encoding
'cp437'
and also in IDLE with a different encoding:
>>> s='850hPa±'
>>> s
'850hPa\
All
I have a string that has a bunch of numbers with the units attached to them.
I want to strip off the units. I am using a regular expression and sub to
do this. This works great for almost all of the cases.
These are the type of lines:
SigWind: 857hPa, , 21.0C, 20.1C, 210 @ 9
