On Feb 2, 2005, at 10:19, Ewald Ertl wrote:
Hi!
Using binary operations:
a='0x87BE'
str(hex(int(a,16) & 0xFF))
'0xbe'
str(hex((int(a,16) & 0xFF00) / 0xFF))
'0x87'
HTH Ewald
Actually, the int conversions aren't even necessary.
>>> hex(0x87BE & 0xFF)
'0xbe'
>>> hex((0x87BE & 0xFF00) / 0xFF)
'0x8
Hi!
Using binary operations:
>>> a='0x87BE'
>>> str(hex(int(a,16) & 0xFF))
'0xbe'
>>> str(hex((int(a,16) & 0xFF00) / 0xFF))
'0x87'
>>>
HTH Ewald
on Wed, 2 Feb 2005 15:10:36 +0800 jrlen balane <[EMAIL PROTECTED]> wrote :
---
i have a 4 digit hex number (2 bytes) and i want to separate it into 2
digit hex (1 byte each) meaning i want to get the upper byte and the
lower byte since i am going to add this two.
how am i going to do this?
should i treat it just like a normal string?
please help, thanks.
ex. hexa = '0x87BE"
