On Thu, Nov 10, 2011 at 8:48 PM, Steven D'Aprano wrote:
> lina wrote:
>>
>> Hi,
>>
>> How to remove the coming duplication,
>>
>> Here I wrote one (not working):
>>
>>
> a=['2', '5', '7', '5', '5']
>
> [...]
>>
>> I wish to get a is [2,5,7,5]
>>
>> just remove the coming duplication, not uniqu
lina wrote:
Hi,
How to remove the coming duplication,
Here I wrote one (not working):
a=['2', '5', '7', '5', '5']
[...]
I wish to get a is [2,5,7,5]
just remove the coming duplication, not unique the list.
a = [2, 5, 7, 5, 5]
b = a[0:1] # slice of the first item only
for x in a[1:]: #
On 2011-11-10 09:26, lina wrote:
atoms=[]
def fetchonefiledata(infilename):
for line in open(infilename,"r"):
parts=line.strip().split()
atoms=parts[2]
print(atoms[0])
First you define "atoms" as an empty list, but in the line
atoms
Asokan Pichai wrote:
> On Thu, Nov 10, 2011 at 2:07 PM, Peter Otten <__pete...@web.de> wrote:
>
>> Christian Witts wrote:
>>
>> > def remove_coming_duplication(a_list):
>> > return [element for idx, element in enumerate(a_list) if element
>> > !=
>> > a_list[idx-1]]
>>
>> Beware of nega
On Thu, Nov 10, 2011 at 2:07 PM, Peter Otten <__pete...@web.de> wrote:
> Christian Witts wrote:
>
> > def remove_coming_duplication(a_list):
> > return [element for idx, element in enumerate(a_list) if element !=
> > a_list[idx-1]]
>
> Beware of negative indices:
>
> >>> remove_coming_duplica
Christian Witts wrote:
> def remove_coming_duplication(a_list):
> return [element for idx, element in enumerate(a_list) if element !=
> a_list[idx-1]]
Beware of negative indices:
>>> remove_coming_duplication([1, 2, 1])
[2, 1] # should be [1, 2, 1]
Thanks for all, I found the problems I faced is more tricky than the
simple list I gave.
Here the list is: a row of numbers, not one number,
such as print a_list[1] is:
1
1
9
7
7
9
9
9
print(a_list) is:
617
617
790
571
571
790
790
790
I attached the codes written based on the suggestions al
I was so miffed at not reading the OP's
mail carefully that I wrote a one liner.
Ok. Here it goes:
def no_adjacent_dup(lst):
return [ x for x, y in zip(lst, lst[1:]) if x != y] + [lst[-1]]
:-) Enjoyed working that one out; but whether it is a good solution
Asokan Pichai
On 2011/11/10 09:10 AM, lina wrote:
Hi,
How to remove the coming duplication,
Here I wrote one (not working):
a=['2', '5', '7', '5', '5']
for i in range(len(a)-1):
if a[i+1]==a[i]:
a.remove(a[i+1])
if i not in range(len(a)):
break
a
BlackBerry wireless device from MTN
-Original Message-
From: lina
Sender: tutor-bounces+delegbede=dudupay@python.org
Date: Thu, 10 Nov 2011 15:20:49
To: tutor
Subject: Re: [Tutor] how to remove the coming duplication
b = []
b=b.append(a[i]) for i in range(len(a)) if a[i] != b[-1
Hello,
list.remove will remove the first occurrence of the value from the list. So
the output is expected as far as Python is concerned.
May be you should think about using pop function.
Please take a look at the code below
>>> def RemoveComingDuplicates(a):
for i in range(len(a)-1):
print i,i+
ry wireless device from MTN
-Original Message-
From: lina
Sender: tutor-bounces+delegbede=dudupay@python.org
Date: Thu, 10 Nov 2011 15:10:57
To: tutor
Subject: [Tutor] how to remove the coming duplication
Hi,
How to remove the coming duplication,
Here I wrote one (not working):
>>&g
Bad to reply to my own post.
Failed to understand the
>> just remove the coming duplication, not unique the list.
Sorry; ignore my ideas
Asokan Pichai
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>>> for i in range(len(a)):
if i == 0:
b.append(a[i])
if a[i]!=b[-1]:
b.append(a[i])
This one seems work, but looks clumsy,
Thanks for any suggestions that helps to improve.
Best regards,
___
Tutor mailli
On Thu, Nov 10, 2011 at 12:40 PM, lina wrote:
> Hi,
>
> How to remove the coming duplication,
>
> Here I wrote one (not working):
>
>
> >>> a=['2', '5', '7', '5', '5']
> >>> for i in range(len(a)-1):
>if a[i+1]==a[i]:
>a.remove(a[i+1])
>if i not in range(len(a)):
>
b = []
b=b.append(a[i]) for i in range(len(a)) if a[i] != b[-1]
showed me:
SyntaxError: invalid syntax
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Hi,
How to remove the coming duplication,
Here I wrote one (not working):
>>> a=['2', '5', '7', '5', '5']
>>> for i in range(len(a)-1):
if a[i+1]==a[i]:
a.remove(a[i+1])
if i not in range(len(a)):
break
>>> a
['2', '7', '5', '5']
I wish
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