Hello Lina!
On Wednesday 18.05.2011 05:22:50 lina wrote:
> May I ask another question:
>
> where I can get some advanced, terse and powerful python tutorials.
> short but powerful and a bit hard to understand at first.
The tutorial on Python's website is relatively terse, but it uses a simple
"lina" wrote
where I can get some advanced, terse and powerful python tutorials.
short but powerful and a bit hard to understand at first.
The Python web site has many tutorials listed:
http://wiki.python.org/moin/BeginnersGuide/Programmers
Your definition of advanced, terse and powerful ma
On Wed, May 18, 2011 at 2:30 AM, Michiel Overtoom wrote:
> On 2011-05-17 18:47, lina wrote:
>
>> A further question: I don't know how can I get the final output is
>> unique?
>
> Unique in what way? You mean that in file1 (confout.pdb?) there could be
> more values for the same key? or should dup
May I ask another question:
where I can get some advanced, terse and powerful python tutorials.
short but powerful and a bit hard to understand at first.
Thanks again,
On Wed, May 18, 2011 at 1:51 AM, Emile van Sebille wrote:
> On 5/17/2011 9:47 AM lina said...
>>
>> A further question: I don'
On 2011-05-17 18:47, lina wrote:
A further question: I don't know how can I get the final output is unique?
Unique in what way? You mean that in file1 (confout.pdb?) there could be
more values for the same key? or should duplicate lines in the output be
condensed to one line? Maybe if you w
On 5/17/2011 9:47 AM lina said...
A further question: I don't know how can I get the final output is unique?
That'll require some rework. The mapping container replaces
mapping[parts[0]] each time it encounters another parts[0].
You can test if you are about to add a new entry or replace
an e
A further question: I don't know how can I get the final output is unique?
#!/bin/python
mapping={}
for line in open("confout.pdb").readlines():
parts=line.strip().split()
if len(parts)>6:
mapping[parts[1]]=parts[4]+parts[3]
origs=open("dummy.atomID").read().split()
print " ".joi
Thanks, it works.
On Tue, May 17, 2011 at 11:53 PM, Emile van Sebille wrote:
> On 5/17/2011 8:31 AM lina said...
>>
>> Following Michiel's code (a little adjustment was done):
>>
>
> Well. you're almost there. The error you're getting
> is likely due to splitting an empty line, then referencing
On 5/17/2011 8:31 AM lina said...
Following Michiel's code (a little adjustment was done):
Well. you're almost there. The error you're getting
is likely due to splitting an empty line, then referencing
the [1] and [4] elements.
After you split the line into parts, test to confirm
that the fi
I learn python on and off,
tried some examples, I mean tutorial, step by step writing around 80
ones, but seems not a good way of learning. Those tutorials are good,
just I am not good at learning. so what I learned can't handle the
problem I met.
On Tue, May 17, 2011 at 11:19 PM, lina wrote:
>
$ python atomToResidues.py
Traceback (most recent call last):
File "atomToResidues.py", line 6, in
mapping[parts[1]]=parts[4]
IndexError: list index out of range
Following Michiel's code (a little adjustment was done):
#!/bin/python
mapping={}
for line in open("confout.pdb").readlines():
On 5/17/2011 6:42 AM lina said...
Hi,
For file1:
5007 O28 CHO 173 35.300 99.430 65.810 1.00 0.0
5008 H29 CHO 173 35.680 100.290 66.150 1.00 0.00
5009 C1 CHO 174 59.060 12.440 58.680 1.00 0.00
5010 C2 CHO 174 59.460 12.480 60.160 1.00
On 2011-05-17 15:42, lina wrote:
> I want to get the $4(column 4) value which has the $1 value. for
> values in file2
Have you tried to write some code yourself already? Please show it.
Anyway, I'd proceed with something like this:
mapping={}
for line in open("file1").readlines():
parts=
First read file1, and keep the result in a useful data structure (for
this simple case it can be nothing more than a dictionary with the
value in column 1 as key and the value in column 4 as value, but
perhaps it's better to find something else if you want to do more with
the data). Then go through
Hi,
For file1:
5007 O28 CHO 173 35.300 99.430 65.810 1.00 0.0
5008 H29 CHO 173 35.680 100.290 66.150 1.00 0.00
5009 C1 CHO 174 59.060 12.440 58.680 1.00 0.00
5010 C2 CHO 174 59.460 12.480 60.160 1.00 0.00
5011 C3 CHO 174 59.590
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