* Fosiul Alam [2016-01-05 09:46]:
> Hi
> so the logic will be like bellow :-
>
> a)Start to read the file,
> b)start a line which start with "3600601"
> c) Iterate through the line till i see another line which starts with
> "3600601"
> d) read the last line before 3600601
> e)cut all the path a
Hi
so the logic will be like bellow :-
a)Start to read the file,
b)start a line which start with "3600601"
c) Iterate through the line till i see another line which starts with
"3600601"
d) read the last line before 3600601
e)cut all the path and create a dictionary which will have one key (LUN I
* Fosiul Alam [2016-01-04 22:29]:
> Hi Expert,
> I am learning python to do some system admin code, i am still in the
> process of learning but I need a help on bellow code in urgent, i will be
> really greatfull for any help
>
> Basically i wanted like this :-
>
> grep a line which has 1:0:0:12
On Mon, Jan 4, 2016 at 2:29 PM, Fosiul Alam wrote:
> Hi Expert,
> I am learning python to do some system admin code, i am still in the
> process of learning but I need a help on bellow code in urgent, i will be
> really greatfull for any help
Question: how would you do this task with regular Uni
Hi Expert,
I am learning python to do some system admin code, i am still in the
process of learning but I need a help on bellow code in urgent, i will be
really greatfull for any help
Basically i wanted like this :-
grep a line which has 1:0:0:129 , and get the LUN number(i.e
36006016565656563434
