Hi,
a = [4,3,2,6,7,9]
b = [8,6,3,3,2,7]
You can turn this into a list of two element tuples with zip():
>>> zip(a,b)
[ (4,8),(3,6,),(2,3),(6,3),(7,2),(9,7) ]
Now you can loop through that and compare both elements, for instance I
believe this list comprehension is what you're looking for:
[ t[0
On Wednesday 26 December 2007 10:03, Alan Gauld wrote:
> I thought I was following this but now I'm not sure.
>
> Do you mean that if I have a list L that contains an arbitrary
>
> number of sublists that I can call zip using:
> >>> zip(*L)
>
> rather than
>
> >>> zip(L[0],L[1],, L[n])
>
> If s
"Chris Fuller" <[EMAIL PROTECTED]> wrote
> "Arbitrary" means any size, and particularly, an unknown size. If
> you don't
> know how big the list is when you are writing the code, you need to
> use this
> syntax.
>
> It's also more concise and less error prone than zip(l[0], l[1],
> l[2]) if yo
"Arbitrary" means any size, and particularly, an unknown size. If you don't
know how big the list is when you are writing the code, you need to use this
syntax.
It's also more concise and less error prone than zip(l[0], l[1], l[2]) if you
have got a 2D list of known length.
On Wednesday 26 D
Chris Fuller wrote:
> I didn't think of that. But for an arbitrary 2D list, you need the asterisk
> syntax.
I don't know what you mean by "an arbitrary 2D list". You need the *
syntax when your arguments are *already* in a list. For any number of
arguments,
zip(*[a, b, ..., x, y, z])
can be
I didn't think of that. But for an arbitrary 2D list, you need the asterisk
syntax.
On Tuesday 25 December 2007 19:00, you wrote:
> Chris Fuller wrote:
> zip(*[a,b])
> >
> > [(4, 8), (3, 6), (2, 3), (6, 3), (7, 2), (9, 7)]
>
> This can be just zip(a, b)
>
> Kent
___
Chris Fuller wrote:
zip(*[a,b])
> [(4, 8), (3, 6), (2, 3), (6, 3), (7, 2), (9, 7)]
This can be just zip(a, b)
Kent
___
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
The most concise way to do this is to transpose the list (convert a axb array
to bxa), then complare the elements that are pairs of one value each of the
original lists.
You have two lists, a and b. Put these into a list and you have a 2x6
2d "array".
>>> [a,b]
[[4, 3, 2, 6, 7, 9], [8, 6, 3, 3
sith . wrote:
> sith . wrote:
>> Hi,
>> I've read the posts on comparing 2 lists and couldn't find the answer to
>> my question.
>> I have 2 lists
>> a = [4,3,2,6,7,9]
>> b = [8,6,3,3,2,7]
>> How can I determine if the elements in a are larger or smaller than the
>> elements in b.
>>
>> for i in a
"sith ." wrote:
> How can I determine if the elements in a are larger or smaller than
> the elements in b.
> ..
> like 2 columns in excel, the third column would be
> a new list of boolean values. Can someone help please? Thank you.
Hi,
in that case, you need to create the third column (list).
"sith ." <[EMAIL PROTECTED]> wrote
> I'd like
> 4 to 8,
> 3 to 6,
> 2 to 3 and so on; like 2 columns in excel, the third column would be
> a new list of boolean values.
results = [ A[n] == B[n] for n in len(A) ]
You should check that A and B are equal lengths of course...
You could also subst
"sith ." <[EMAIL PROTECTED]> wrote:
> How can I determine if the elements in a are larger or smaller than
> the elements in b.
> ..
> like 2 columns in excel, the third column would be
> a new list of boolean values. Can someone help please? Thank you.
Hi,
in that case, you need to create the t
sith . wrote:
> Hi,
> I've read the posts on comparing 2 lists and couldn't find the answer to
> my question.
> I have 2 lists
> a = [4,3,2,6,7,9]
> b = [8,6,3,3,2,7]
> How can I determine if the elements in a are larger or smaller than the
> elements in b.
>
> for i in a:
> for u in b:
>
sith . wrote:
> Hi,
> I've read the posts on comparing 2 lists and couldn't find the answer to
> my question.
> I have 2 lists
> a = [4,3,2,6,7,9]
> b = [8,6,3,3,2,7]
> How can I determine if the elements in a are larger or smaller than the
> elements in b.
>
> for i in a:
> for u in b:
>
Hi,
I've read the posts on comparing 2 lists and couldn't find the answer to my
question.
I have 2 lists
a = [4,3,2,6,7,9]
b = [8,6,3,3,2,7]
How can I determine if the elements in a are larger or smaller than the
elements in b.
for i in a:
for u in b:
i > u
does not retu
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