On 10/28/2011 01:38 AM, Praveen Singh wrote:
splitWord('google', 2)
['go', 'og', 'le']
>>> splitWord('google', 3)
['goo', 'gle']
>>> splitWord('apple', 1)
['a', 'p', 'p', 'l', 'e']
>>> splitWord('apple', 4)
['appl', 'e']
def splitWord(word, number):
.
> Thanks Christian for your links and code
>
>
> ___
> Tutor maillist - Tutor@python.org
>
> To unsubscribe or change subscription
> options:http://mail.python.org/mailman/listinfo/tutor
>
>
> Below [1] is how I would write it, which is simply a
On 2011/10/28 07:38 AM, Praveen Singh wrote:
>>> splitWord('google', 2)
['go', 'og', 'le']
>>> splitWord('google', 3)
['goo', 'gle']
>>> splitWord('apple', 1)
['a', 'p', 'p', 'l', 'e']
>>> splitWord('apple', 4)
['appl', 'e']
def splitWord(w
Hi Praveen
I am still new to the language but here is what I would do. Sorry I can't
comment on how to best check for efficiency.
my_str='google'
split_by= 2
[ my_str[i:i+split_by] for i in range(0, len(my_str), split_by) ]
Just using a list comprehension.
best,
-Abhi
On Thu, Oct 27, 2011 a
>>> splitWord('google', 2)
['go', 'og', 'le']
>>> splitWord('google', 3)
['goo', 'gle']
>>> splitWord('apple', 1)
['a', 'p', 'p', 'l', 'e']
>>> splitWord('apple', 4)
['appl', 'e']
def splitWord(word, number):
length=len(word)
list1=[]
x=0
