On 1/15/11, Alan Gauld wrote:
> "Alex Hall" wrote
>
>> m=int(m)
>> just before the if statement. This causes m to turn from a string
>> into
>> an integer and is what is known as "casting" or "type casting", if I
>> have my vocabulary correct.
>
> Sadly you don't although its a common error.
>
>
"Alex Hall" wrote
m=int(m)
just before the if statement. This causes m to turn from a string
into
an integer and is what is known as "casting" or "type casting", if I
have my vocabulary correct.
Sadly you don't although its a common error.
This is type conversion. You are actually changing
On 01/-10/-28163 02:59 PM, walter weston wrote:
I generate a random number(supposedly a password, in my case its just a long
floating point lol),I want the user to reinput that number and I want to print
a string if the number entered is correct. so if m==num(num is the number
generated and m
Adding reply to list -
On Sat, Jan 15, 2011 at 2:55 AM, walter weston wrote:
> I only want to generate a random number once
>
Then you don't need a for loop. Think of a for loop as something you
need when you want to run a piece of code several times, for example
for x in range(1,6):
print('
> import random
> for x in range(0,1):
> num = random.random()
> print (num)
> m=input('input pass:')
> if m==num:
> print('you entered correctly, proceed')
Your problem lines in the differences in between the types - your num
variable is a float, whereas your m variable i
On 1/14/11, walter weston wrote:
>
> I generate a random number(supposedly a password, in my case its just a long
> floating point lol),I want the user to reinput that number and I want to
> print a string if the number entered is correct. so if m==num(num is the
> number generated and m is the va
I generate a random number(supposedly a password, in my case its just a long
floating point lol),I want the user to reinput that number and I want to print
a string if the number entered is correct. so if m==num(num is the number
generated and m is the variable which stores the input ) then I w
