I would always use the os functions to find the basename, but
You could exploit the fact that Windows considers the extension to be
whatever is after the last "." character.
fn = fn[:fn.rfind(".")]
>> > What I found is this:
>> > import os
>> > myfile_name_with_path = 'path/to/my/testfile.txt'
>
> > What I found is this:
> > import os
> > myfile_name_with_path = 'path/to/my/testfile.txt'
> > basename = os.path.basename(myfile_with_path)
> > filename = os.path.splitext(basename)
> > myfile_name_without_suffix = filename[0]
>
> The last two can be easily combined as:
>
> > myfile_name_with
"Timmie" <[EMAIL PROTECTED]> wrote
> What is the easiest and fastes way to get the basename
> of a file wihout extension?
>
> What I found is this:
> import os
> myfile_name_with_path = 'path/to/my/testfile.txt'
> basename = os.path.basename(myfile_with_path)
> filename = os.path.splitext(basen
Timmie wrote:
> Hello,
> I would like to get the name of a file without it's extension/suffix.
>
> What is the easiest and fastes way to get the basename
> of a file wihout extension?
>
> What I found is this:
> import os
> myfile_name_with_path = 'path/to/my/testfile.txt'
> basename = os.path.ba
Hello,
I would like to get the name of a file without it's extension/suffix.
What is the easiest and fastes way to get the basename
of a file wihout extension?
What I found is this:
import os
myfile_name_with_path = 'path/to/my/testfile.txt'
basename = os.path.basename(myfile_with_path)
filename
