oddly enough, i get different results doing it the "old-fashioned" way:
$ sqrt.py
using **
0.000447034835815
using sqrt()
0.000399112701416
$ sqrt.py
using **
0.00043797492981
using sqrt()
0.000399827957153
$ sqrt.py
using **
0.00043797492981
using sqrt()
0.000402927398682
here's the code snipp
"Eric Brunson" <[EMAIL PROTECTED]> wrote
>> t = timeit.Timer( "sqrt(12)", "from math import sqrt" )
>> print t.timeit(1000)
>>> 7.17679214478
> timeit.Timer("import math; math.sqrt(64)").timeit(1000)
>> 0.002298138362618829
> timeit.Timer("import math; 64 ** 0.5").timeit(1000
Alan Gauld wrote:
> "Eric Brunson" <[EMAIL PROTECTED]> wrote
>
>
> import timeit
> t = timeit.Timer( "12 ** .5" )
> print t.timeit(1000)
>
>> 2.29147315025
>>
> t = timeit.Timer( "sqrt(12)", "from math import sqrt" )
> print t.timeit(1000)
>
"Eric Brunson" <[EMAIL PROTECTED]> wrote
> >>> import timeit
> >>> t = timeit.Timer( "12 ** .5" )
> >>> print t.timeit(1000)
> 2.29147315025
> >>> t = timeit.Timer( "sqrt(12)", "from math import sqrt" )
> >>> print t.timeit(1000)
> 7.17679214478
>
> Looks like ** is about three times fast
Elaine wrote:
> Does anyone know which is the more efficient way of
> finding a square root in Python:
>
> sqrt(x) or x ** 0.5
>
I dunno, let's check:
>>> import timeit
>>> t = timeit.Timer( "12 ** .5" )
>>> print t.timeit(1000)
2.29147315025
>>> t = timeit.Timer( "sqrt(
Does anyone know which is the more efficient way of
finding a square root in Python:
sqrt(x) or x ** 0.5
???
Thanks,
Elaine
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